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andrew11 [14]
3 years ago
6

Most of the elements to the left of the stair-step line in the periodic table exist as _________ in the periodic table.

Chemistry
1 answer:
miv72 [106K]3 years ago
3 0
D would be the answer as they are metals
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I will help you with answering this question.
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3 years ago
The elements in a row of the the periodic table​
Aleks [24]

Answer:

<em><u>Rows in the periodic table are called periods</u></em>. As one moves from left to right in a given period, the chemical properties of the elements slowly change. <em><u>Columns in the periodic table are called groups</u></em>. Elements in a given group in the periodic table share many similar chemical and physical properties

Explanation:

5 0
2 years ago
A gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from ___
Anettt [7]
Initial volume is 8.5. Could I get best answer??
3 0
3 years ago
The correct sequence where reactivity towards oxygen increases.
ziro4ka [17]

Answer:

Option D is good to go!

Explanation: as per the reactivity series more reactive substances will react with the counterpart substance.The most reactive substance here is calcium while the least reactive is aluminium, the magnesium comes in between.As per their reactivity, these substances will react with oxygen.

Explanation:

3 0
3 years ago
4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
3 years ago
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