Answer: The initial temperature of the iron was 
Explanation:
As we know that,
![m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_%7Bfinal%7D-T_1%29%3D-%5Bm_2%5Ctimes%20c_2%5Ctimes%20%28T_%7Bfinal%7D-T_2%29%5D)
.................(1)
where,
q = heat absorbed or released
= mass of iron = 360 g
= mass of water = 750 g
= final temperature = 
= temperature of iron = ?
= temperature of water = 
= specific heat of iron = 
= specific heat of water= 
Now put all the given values in equation (1), we get
![-360\times 0.450\times (46.7-x)=[750\times 4.184\times (46.7-22.5)]](https://tex.z-dn.net/?f=-360%5Ctimes%200.450%5Ctimes%20%2846.7-x%29%3D%5B750%5Ctimes%204.184%5Ctimes%20%2846.7-22.5%29%5D)
Therefore, the initial temperature of the iron was
Answer:
(A) The intermolecular attraction between HF molecules are stronger than between HCl molecules mainly to due hydrogen bonding.
Explanation:
Since Flourine is highly electronegative and as such, when it bonds with Hydrogen it forms a hydrogen bond. Whereas the HCL molecule is a polar molecule whose inter-molecular forces are dipole dipole interactions. Although a Hydrogen bond is a type of dipole dipole interaction it is stronger than the traditional dipole dipole forces and London dispersion forces. HF also has a shorter bond length which makes the bond and inter-molecular forces stronger as compared to HCL.
Answer: The Earth is an oblate spheroid which is more elongated along the equator.
Regions along the equator receives more amount of direct sunlight from the sun causing higher temperatures along the region. While places along the poles receives less amount of heat since heat is scattered in a larger area due to the shape of the Earth around the poles.
Explanation: So places along the equator experiences higher temperature due to the direct hit of sunlight. And places along the polar regions experiences cooler temperature since it receives less amount of sunlight.
The mass of the water in the container given the data from the question is 22.5 g
<h3>Data obtained from the question</h3>
- Mass of cold lead (M) = 54.3 g
- Temperature of lead (T) = 384.4 K
- Temperature of water (Tᵥᵥ) = 291.2 K
- Equilibrium temperature (Tₑ) = 297.6 K
- Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gK
- Specific heat capacity of lead (C) = 0.128 J/gK
- Mass of water (Mᵥᵥ) = ?
<h3>How to determine the mass of water </h3>
Heat loss = Heat gain
MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
54.3 × 0.128 (384.4 – 297.6) = Mᵥᵥ × 4.184(297.6 – 291.2)
6.9504 × 86.8 = Mᵥᵥ × 4.184 × 6.4
Divide both side by 4.184 × 6.4
Mᵥᵥ = (6.9504 × 86.8) / (4.184 × 6.4)
Mᵥᵥ = 22.5 g
Learn more about heat transfer:
brainly.com/question/6363778
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