How are the elements arranged in the modern periodic table g?

An element is a pure substance in which there are how many kinds of atoms?

Ostrovityanka [42]

Answer:

One

Explanation:

An element is a pure substance in which there are only one kind of atom. Elements are distinct substances that cannot be split up into simpler substances.

Such substances consists of only one kind of atom. There are over a hundred known elements to date.

Generally, as a pure substance, the composition of an element is definite and they are homogenous in all parts.

8 0

2 years ago

What is the volume of 3.00 M sulfuric aid that contain 9.809 g of H2SO4 (98.09g/mol)

Slav-nsk [51]

Given :

Molarity of sulfuric acid solution is 3.0 M.

Amount of sulfuric acid present in solution is 9.809 g.

To Find :

The volume of solution.

Solution :

We know, molarity is given by :

$Molarity = \dfrac{number \ of \ moles \times 1000}{Volume\ ( ml )}\\\\M = \dfrac{w \times 1000}{M.M \times V}\\\\3 = \dfrac{9.809\times 1000}{98.09 \times V}\\\\V = \dfrac{1000}{10\times 3}\ ml\\\\V = 33.33 \ ml$

Therefore, volume required is 33.33 ml .

5 0

3 years ago

If I use the dropper to add 10 mL of drink mix to 50 mL of water, what is the

Yuliya22 [10]

Answer:

16.7%

Explanation:

From the question given above, the following data were obtained:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Percentage of drink mix =?

Next, we shall determine the total volume of the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Volume of water = 50 mL

Total volume of solution =?

Total volume of solution = (Volume of drink mix) + (Volume of water)

Total volume of solution = 10 + 50

Total volume of solution = 60 mL

Finally, we shall determine the percentage of the drink mix in the solution. This can be obtained as follow:

Volume of drink mix = 10 mL

Total volume of solution = 60 mL

Percentage of drink mix =?

Percentage of drink mix = Vol. of drink mix / total volume × 100

Percentage of drink mix = 10/60 × 100

Percentage of drink mix = 16.7%

4 0

3 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$