Ask question

Ask question

All categories

3 years ago

14

How are the elements arranged in the modern periodic table g?

1 answer:

Yuri [45]3 years ago

3 0

Rows and numbers and periods

You might be interested in

Use the balanced equation given below to solve the problem that follows: Calculate the mass in grams of water produced along wit

saveliy_v [14]

Answer: 1.98 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given volume}}{\text{Molar volume}}$

$\text{Moles of} CO_2=\frac{5.0L}{22.4L}=0.22moles$

The balanced given equation is:

$C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)$

According to stoichiometry :

4 moles of $CO_2$ will produce = 2 moles of $H_2O$

Thus 0.22 moles of $CO_2$ will produce= $\frac{2}{4}\times 0.22=0.11moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=0.11moles\times 18g/mol=1.98g$

Thus 1.98 g of water is produced along with 5.0 L of $CO_2$ at STP

6 0

3 years ago

The molecule shown is a

Pani-rosa [81]

c is the answer a benzene

8 0

3 years ago

What is the number at the end of an isotope’s name?

Taya2010 [7]

Explanation:

5 I don't know what is the answer if I got it wrong

8 0

3 years ago

Read 2 more answers

To fine the number of neutrons in an atom, subtract its_____

storchak [24]

a is the answer hope this helps

3 0

3 years ago

Water vapor enters a compressor at 35 kpa and 160°c and leaves at 300 kpa with the same specific entropy as at the inlet. What a

Annette [7]

<h3><em><u>solution</u></em><em><u>:</u></em></h3>

<em><u>The initial entropy is obtained from the initial pressure and temperature with data from A-6 using interpolation:</u></em>

<em><u>s</u></em><em><u>=</u></em><em><u> </u></em><em><u>8</u></em><em><u>.</u></em><em><u>26</u></em><em><u>5</u></em><em><u>2</u></em><em><u> </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kgK</u></em>

<em><u>The final temperature is determined from the entropy and the final pressure with data from A-6 using interpolation:</u></em>

<em><u>T₂ = T₁+</u></em><em><u> </u></em><em><u>T₂ - </u></em><em><u>T₁</u></em><em><u>/</u></em><em><u> </u></em><em><u>8</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8</u></em><em><u>₁</u></em><em><u> </u></em><em><u>(</u></em><em><u> </u></em><em><u>s</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u>)</u></em>

<em><u>= </u></em><em><u>(</u></em><em><u>400 +</u></em><em><u> </u></em><em><u>500 - 400</u></em><em><u>/</u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u> </u></em><em><u>(8.2652 - 8</u></em><em><u>)</u></em><em><u>)</u></em>

<em><u>= 478.83°C</u></em>

<em><u>The final enthalpy is determined in the same way:</u></em>

<em><u>h₂= h₁</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>h₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>h₁</u></em><em><u>/</u></em><em><u>s</u></em><em><u>₂</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>s</u></em><em><u>₁</u></em><em><u> </u></em><em><u>( s - s₁)</u></em>

<em><u>= (</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>+</u></em><em><u> </u></em><em><u>3486.6 </u></em><em><u>-</u></em><em><u> </u></em><em><u>3275.5</u></em><em><u>/</u></em><em><u> </u></em><em><u>8.3271</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>8.0347</u></em><em><u>)</u></em><em><u> </u></em><em><u>(8.265</u></em><em><u>)</u></em>

<em><u>=</u></em><em><u> </u></em><em><u>3441.91 </u></em><em><u>kJ</u></em><em><u>/</u></em><em><u>kg</u></em>

6 0

2 years ago