Tape Diagrams and Writing Equations

Mathematics

1 answer:

notka56 [123]3 years ago

8 0

Answer:

3x + 16 = 22.75

3 = 22.75 - 16

3× = 6.75

3 3

x= 2.25

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Jasper's lawn is 3/4 of an acre in size. The fertilizer bag states that 5 1/2 bags are required for 1 acre. How many bags does J

Nady [450]

Answer: $4\dfrac{1}{8}\ \text{bags}$

Step-by-step explanation:

Given

Jasper lawn is three-fourth of an acre

1 acre of land requires $5\frac{1}{2}$ bags

convert mixed numeral to fraction

$\Rightarrow 5\dfrac{1}{2}=\dfrac{11}{2}$

$\therefore 1\ \text{acre}\equiv\dfrac{11}{2}\ \text{bags}\\\\\Rightarrow \dfrac{3}{4}\ \text{acre}\equiv \dfrac{11}{2}\times \dfrac{3}{4}=\dfrac{33}{8}\ \text{bags}$

$\Rightarrow \dfrac{33}{8}\ \text{bags}=4\dfrac{1}{8}\ \text{bags}$

8 0

3 years ago

Anais bought 3 1/2 yards of ribbon. She had 2 feet 10 inches of ribbon left after trimming some curtains. How many inches of rib

Lesechka [4]

First, convert how many yards there were to inches. 3 1/2 yards gets you 126 inches. Next, find out how many inches 2 feet and 10 inches of ribbon is. 34 is your answer. Subtract 34 from 126 to get an answer of 92 inches (7 feet, 6 inches.)

4 0

3 years ago

3(9-8x-4x)+8(3x+4)=11 how do I work this out???

Arte-miy333 [17]

Remember PEMDAS is the order of operations. parenthesis,exponents,multiply,divide,add,subtract. so -8x-4x is -12x. now simplified the problem is 3(9-12x) + 8(3x+4)=11 . now I would distribute the numbers before the parentheses and it becomes 27-36x + 24x+32 =11 . now combine like terms. 59-12x =11 . subtract 59 on both sides. -12x=-48. divide -12 on both sides. x=4. :-)

7 0

3 years ago

A study on the latest fad diet claimed that the amounts of weight lost by all people on this diet had a mean of 23.2 pounds and

erica [24]

Answer:

The standard deviation of the sampling distribution of sample means would be 0.8186.

Step-by-step explanation:

We are given that

Mean of population=23.2 pounds

Standard deviation of population=6.6 pounds

n=65

We have to find the standard deviation of the sampling distribution of sample means.