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umka2103 [35]
2 years ago
15

How can a student collect and measure the volume of a gas produced ?

Chemistry
1 answer:
Anastasy [175]2 years ago
8 0

The volume of oxygen produced can be measured using the gas syringe method. The gas collects in the syringe, pushing out against the plunger. The volume of gas that has been produced can be read from the markings on the syringe.

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Please help. I’m terrible with weather
Harrizon [31]

first know the difference between the 4 seasons or weather's that occur and that will help get through

4 0
3 years ago
Arsenic has one stable isotope:75/33 As.
algol13
The answer is 42 neutrons
6 0
3 years ago
Consider the following intermediate chemical equations. 3 equations. 1: upper C upper H subscript 4 (g) right arrow upper C (s)
ladessa [460]

The enthalpy of the reaction is the amount of energy absorbed or lost in the reaction. The enthalpy of the final reaction  is -113.4 kJ.

<h3>What are intermediate reactions?</h3>

The intermediate reactions are the small reactions that takes place in order to achieve the final reaction product.

The given intermediate reactions are:

\rm CH_4\;\rightarrow\;C\;+\;2\;H_2......\Delta H_1=74. 8\;kJ\\CCl_4\;\rightarrow\;C\;+\;2\;Cl_2......\Delta H_2=95. 7\;kJ\\H_2\;+\;Cl_2\;\rightarrow\;2\;HCl......\Delta H_3=-92. 3\;kJ

The final reaction to be achieved is:

\rm CH_4\;+\;4\;Cl_2\;\rightarrow\;CCl_4\;+\;4\;HCl

The second reaction is reversed in order to achieve the final reaction product.

The enthalpy of the final reaction (\Delta H_{rxn}) is given as:

\Delta H_{rxn}=\Delta H_1-\Delta H_2+\Delta H_3

Substituting the values of enthalpy:

\Delta H_{rxn}= 74. 8-95. 7+(-92. 3)\text k\text J\\\Delta H_{rxn}=-113.4\;\rm kJ

The final enthalpy of the reaction is -113.4 kJ. Thus, option B is correct.

Learn more about enthalpy of reaction, here:

brainly.com/question/1657608

4 0
2 years ago
In NMR: The size of coupling constants (J values) depend on three factors:
ElenaW [278]

Answer:

True

It is true that he size of coupling constants (J values) depend on three factors:

a. Through bond distance between the protons.

b. Angle between the two C-H bonds.

c. Electronegative substituents.

Explanation:

With the increase in the valence angle the coupling constant reduces. The distance between the carbon atoms also influence coupling constant. With increase in bond length, the coupling constant decreases. Also the more an atom is electronegative, the lesser is the coupling constant

Thus, it is true that he size of coupling constants (J values) depend on three factors:

a. Through bond distance between the protons.

b. Angle between the two C-H bonds.

c. Electronegative substituents.

4 0
2 years ago
What is the wavelength of a 1.32 x 10^-6 eV wave?
sineoko [7]

Answer:

16. What is the wavelength of a 1.32 x 10-6 eV wave?

ν = E /ν = h = 1.32 x 10-6

eV x 1.602 x 10-19

J = 3.191 331 38 x 10+8 s-1

6.626 2 x 10-34J-s 1 eV

λ = c/ν = ν = 3.00 x 108

m/ν = s = 3.00 x 108

m x 1

3.191 331 38 x 10+8 s-1

s 3.191 331 38 x 10+8 s-1

= 0.940 m

Explanation:

The answer is 0.940 m That is unless i messed something up-

7 0
2 years ago
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