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nadezda [96]
3 years ago
5

The ______,

Chemistry
1 answer:
Nitella [24]3 years ago
5 0
Your answer is d: Greeks
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Which scenario supports the ""one gene–one enzyme"" hypothesis of metabolic disease causation?
damaskus [11]

The scenario that supports the "one gene-one enzyme" hypothesis of metabolic disease causation is Phenylketonuria (PKU). This disease (PKU) is caused by the failure to produce a functional variant of an enzyme.

Phenylketonuria (PKU) is a metabolic inherited disorder associated with a decreased metabolism of the amino acid phenylalanine.

PKU is caused by a mutation in the gene responsible for encoding a key enzyme needed to break down phenylalanine.

Untreated PKU may lead to diverse health problems which include brain damage, intellectual disability, seizures, mental disorders, etc.

Learn more in:

brainly.com/question/7157066?referrer=searchResults

4 0
2 years ago
What is the voltage of the voltaic cell Zn|Zn2+||Cu2+|Cu at 298 K if [Zn2+] = 0.2 M and [Cu2+] = 4.0 M? Cu2+ + 2e- → Cu Eo = +0.
OLga [1]

Answer : The voltage of the voltaic cell is 1.14 V

Explanation :

From the given cell representation, we conclude that

The copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

To calculate the E^o{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}

Putting values in above equation, we get:

E^o_{cell}=(+0.34V)-(-0.76V)

E^o_{cell}=1.1V

Now we have to calculate the emf or voltage of the cell.

Using Nernest equation at 298 K :

E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}

where,

n = number of electrons in oxidation-reduction reaction = 2

E_{cell} = ?

Now put all the given values in the above equation, we get:

E_{cell}=1.1-\frac{0.0592}{2}\log \frac{0.2}{4.0}

E_{cell}=1.14V

Therefore, the voltage of the voltaic cell is 1.14 V

5 0
3 years ago
Why does an aerial require two explosions of black powder
GuDViN [60]

Answer:

to launch aerials and also causes the explosions necessary for special effects like noise or colored light.

Explanation:

5 0
1 year ago
According to the equation, 2 H2 + O2 --> 2 H20, how many moles of oxygen are required to convert 12 moles of hydrogen to wate
DerKrebs [107]

Answer:

6 moles of oxygen, or 3O2.

Explanation:

I would build a proportion for this:

\frac{2(2)}{2}  =  \frac{12}{x}  \\ 4x = 24 \\ x = 6

5 0
3 years ago
The element that appears farthest to the is written first in the chemical name of a covalent compound.
Mashcka [7]

Answer: left

Explanation: The element that appears farthest to the

✔ left

is written first in the chemical name of a covalent compound.

3 0
2 years ago
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