Answer:
Theoretical yield of HI is 512 g.
The percent yield for this reaction is 25%.
Explanation:
Moles of hydrogen gas = 3.0 moles
Moles of iodine gas = 2.0 moles
According to reaction 1 mol of hydrogen gas reacts with 1 mol of iodine gas.
Then 3.0 moles of hydrogen gas reacts with 3.0 mol of iodine gas. But there are 2.0 moles of iodine gas. Hence,Iodine is a limiting reagent. The production of HI will depend upon iodine gas moles.
According to reaction , 1 mol of iodine gas gives 2 moles of HI.
Then 2 moles of iodine gas will give:
of HI
Theoretically we will get 4 moles of HI.
Theoretical yield of HI = 4 mol × 128 g/mol= 512 g
Experimental yield of HI = 1.0 mol
= 1 mol × 128 g/mol= 128 g
The percent yield for this reaction is 25%.
Answer:
Acids: HNO₃ and HI
Base: KOH
Explanation:
For the Arrhenius concept, acid is a substance that, in water, produces the hydrogen ion (H⁺), and base in the substance that, in water, produces the hydroxyl ion (OH⁻).
For the first reaction then KOH must produce OH⁻ so its a base, and HNO₃ must produce H⁺ so it's an acid.
For the second one, HI must produce H⁺ so it's an acid. For the concept of Arrhenius, (CH₃)₃N can't be classified as a base or as an acid.
Answer:
Water is a polar solvent
Explanation:
We must know that pure dry hydrogen chloride gas does not show any acidic property.
In fact, when hydrogen chloride is dissolved in water, it breaks up into H3O^+ ions and Cl^- ions. This is possible because water is a polar solvent and assists the ionization of HCl.
In nonpolar solvents such as benzene, hydrogen chloride gas is not ionized hence it does not show any acidic property in a benzene solution.
Answer:
The standard moisture content specification for hard gelatin capsules is between 13 % w/w and 16 % w/w. This value can vary depending upon the conditions to which they are exposed: at low humidity's they will lose moisture and become brittle, and at high humidity's they will gain moisture and soften.
Explanation:
Hope this helps!
The solubility of a substance in water is dependent on the temperature. Thus for
1 & 2: Temperature is the independent variable (the one that changes in the first place) and Solubility is a dependent variable (a variable that changes in response to changes in the independent variable.)
The graph: by convention you shall label the horizontal axis with the independent variable and the vertical axis with the dependent variable. For clarity's sake you shall use the finest scale possible that accommodates for all data provided for both axis. Plot the data points on the graph as if they are points on a cartesian plane.
My teacher made no detailed requirements on the phrasing on titles of solubility curve plots; however, like most other graphs in chemistry, the title shall specify the name of variables presented in this visualization. For instance, "the solubility of 
under different temperatures" might do. You shall refer to your textbooks for such convention.
It is necessary to interpolate to find the solubility at a temperature not given in the table. Start by connecting all given data points with a smooth line; find the vertical line corresponding to temperature = 75 degree Celsius and determine the solubility at the intersection of the vertical line and the trend line. That point shall approximates the solubility of the salt at that temperature.
