Answer:
Explanation:
Let assume that the missing aqueous solution of 4-chlorobutanoic acid = 0.76 M
Then, the dissociation of 4-chlorobutanoic acid can be expressed as:
⇄
+ 
The ICE table can be computed as:
⇄
+ 
Initial 0.76 - -
Change -x +x +x
Equilibrium 0.76 - x x x
![K_a = \dfrac{[\mathsf{C_3H_6ClCO_2^-}] [\mathsf{H^+}]}{\mathsf{[C_3H_6ClCO_2H ]}}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5B%5Cmathsf%7BC_3H_6ClCO_2%5E-%7D%5D%20%5B%5Cmathsf%7BH%5E%2B%7D%5D%7D%7B%5Cmathsf%7B%5BC_3H_6ClCO_2H%20%5D%7D%7D)
![K_a = \dfrac{[x] [x]}{ [0.76-x]}](https://tex.z-dn.net/?f=K_a%20%3D%20%5Cdfrac%7B%5Bx%5D%20%5Bx%5D%7D%7B%20%5B0.76-x%5D%7D)
where:

![3.02*10^{-5} = \dfrac{x^2}{ [0.76-x]}](https://tex.z-dn.net/?f=3.02%2A10%5E%7B-5%7D%20%3D%20%5Cdfrac%7Bx%5E2%7D%7B%20%5B0.76-x%5D%7D)
however, the value of x is so negligible:
0.76 -x = 0.76
Then:


x = 0.00479 M
∴
0.00479 M
= (0.76 - 0.00479) M
= 0.75521 M
Finally, the percentage of the acid dissociated is;
= ( 0.00479 / 0.76) × 100
= 0.630 M
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of
:
Moles of
= 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of
react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of 
1 mole of NaOH react with 1/2 mole of 
0.1241 moles of NaOH react with (1/2)×0.1241 mole of 
Moles of
that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of
:
<u>Concentration of
= 0.7246 M</u>
the ionic bond would be between the potassium, and hydrogen sulfate.
Answer:
Television cause it has a satellite
I believe that would be D] CuSO4(s).