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jok3333 [9.3K]
3 years ago
6

PLEASEEEE HELP

Physics
2 answers:
den301095 [7]3 years ago
8 0

Answer:

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

Explanation:

Given:

Blue light of wavelength λ1 = 435 nm

n2 in diamond = 2.42

Find:

Wavelength of light in  diamond λ2

Computation:

Since the wavelength is smaller, the frequency stays constant. The frequency of vibrations does not shift when they pass from one source to the next.

So,

n1λ1 = n2λ2

(1)(435) = (2.42)λ2

Wavelength of light in  diamond λ2 = 179.75 nm (Approx.)

valina [46]3 years ago
3 0

Answer:

180

Explanation:

got it right on acellus

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What kind of creatures/beings are tieflings?
Nuetrik [128]

Answer:

Tieflings are classed as humanoids, not fiends (and technically it appears to be a bloodline curse, not even having any fiendish blood). Note that being classed as a fiend would also mean the character would be immune to spells that target humanoids, such as Hold Person.

Explanation:

-Hope this Helps

PLS MARK ME BRAINLIEST

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4 0
2 years ago
PLEASE HELP!!
allochka39001 [22]
The answer is c if i have not mistaken
4 0
3 years ago
Read 2 more answers
You overindulged on a delicious dessert, so you plan to work off the extra calories at the gym. To accomplish this, you decide t
iragen [17]

Answer:

17086

Explanation:

We are given that

Weight=5 kg

Distance of elbow from the weight=d=35 cm=\frac{35}{100}=0.35 m

1 m=100 cm

g=9.8m/s^2

Work done  each time on the weight=mgh=5\times 9.8\times 0.35=17.15 J

20%  means 0.20 of food energy=Work done each time on weight

Total work done in each time=\frac{17.15}{0.2}=85.75J

1 food calorie=4186 J

350 food calories=350\times 4186 J

Number of lift needed=\frac{350\times 4186}{85.75}=17086

Hence, you must do 17086 arm raises to work off 350 food calories.

6 0
4 years ago
The ball is launched with total initial energy Einitial = mgho. When it reaches the bottom of the hoops, it now has a potential
NeX [460]

Answer:

  K = m g (h₀ - h_plat)

Explanation:

Let's use energy conservation to solve this problem, write the energy at two points of interest

Initial. Higher

          E_initial = m g h₀

Final. Lower

          E_end = K + Ep

          E_end = ½ m v² + m g h_plat

Energy is conserved

          E_initial = E_end

          m g h₀ = K + m g h_plat

          K = m g (h₀ - h_plat)

4 0
3 years ago
100m with a constant speed 200km/hr the pilot drops abomb from the plane. determine (neplect air resistance of friction) X Q​
antiseptic1488 [7]

The horizontal distance XQ traveled by the bomb is 250 m.

<h3>Distance X Q</h3>

Let the XQ be the horizontal distance traveled by the bomb.

<h3>Time for the bomb to drop from 100 m</h3>

h = vt + ¹/₂gt

Let the vertical velocity = 0

h = 0 + ¹/₂gt²

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

t = √(2 x 100 / 9.8)

t = 4.5 s

<h3>Horizontal distance traveled by the bomb</h3>

XQ = vx(t)

where;

vx is horizontal speed, = 200 km/hr = 55.56 m/s

XQ = 55.56 x 4.5

XQ = 250 m

Thus, the horizontal distance XQ traveled by the bomb is 250 m.

Learn more about horizontal distance here: brainly.com/question/24784992

#SPJ1

5 0
2 years ago
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