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3 years ago

Help me solve this please

Mathematics

1 answer:

trasher [3.6K]3 years ago

4 0

Answer:

-1/2

Step-by-step explanation:

2(5y + 3) + 4y = -1

2*5y + 2*3 + 4y = -1

10y + 6 + 4y = - 1 {Combine like terms}

14y + 6 = -1 {Subtract 6 form both sides}

14y = -1 - 6

14y = -7 {Divide both sides by 7}

y = -7/14

y = -1/2

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Two numbers have a difference of 24. What is the sum of their squares if it is a minimum?

seraphim [82]

Let "a" and "b" be some number where:

a - b = 24

We want to find where a^2 + b^2 is a minimum. Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.

So we can first substitute for "a" where a = b+24

So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576

Then we take the derivative and set it equal to zero:

4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12

Thus "a" must equal 12.

So:
a = 12
b = -12

And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.

The smallest sum is 288.

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3 years ago

a recipe calls for 6 cups water and 4 cups of flour if the recipe is increased how many cups of water should be used with 6 cups

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Svetlanka [38]

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Sonbull [250]

Answer:

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Step-by-step explanation:

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Elena L [17]

Answer:

$\sqrt{149\\ \\$

However, that's the length of "c" and you're looking to drag it in. So,o you drag in 10^2+7^2=a^2.

Then, as shown by the first picture attatched, you can drag in the one with "c" and "a" with the five shown.

Step-by-step explanation:

To find "c" the diagonal, as explained, you need to use the theorem twice. You can first use it by finding "a", as you already have "b". To find a, you do 10^2+7^2=a^2, the hypotenuse.

100+49=149.

So, a is root 149.

a^2+b^2=c^2 so

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