Answer:
37064 J
Explanation:
Data Given:
mass of Steam (m) = 16.4 g
heat released (Q) = ?
Solution:
This question is related to the latent heat of condensation.
Latent heat of condensation is the amount of heat released when water vapors condenses to liquid.
Formula used
Q = m x Lc . . . . . (1)
where
Lc = specific latent heat of condensation
Latent heat of vaporization of water is exactly equal to heat of condensation with - charge
So, Latent heat of vaporization of water have a constant value
Latent heat of vaporization of water = 2260 J/g
So
Latent heat of condensation of water will be = - 2260 J/g
Put values in eq. 1
Q = (16.4 g) x (- 2260 J/g)
Q = - 37064 J
So, 37064 J of heat will be released negative sign indicate release of energy
a short thick vein that is formed in each kidney by the convergence of the interlobar veins, leaves the kidney through the hilum, and empties into the inferior vena cava.
To compute for the empirical formula, assume there is 100 grams of the compound. That means there is 40.28 g B, 52.2 g N and 7.53 g H. Convert the mass into moles using their molar masses:
40.28 g B * 1 mol/10.811 g = 3.725835 mol B
52.2 g N * 1 mol/14 g = 3.72857 mol N
7.53 g H * 1 mol/1 g = 7.53 mol H
Divide all the moles by the smallest amount which is 3.725835 mol.
B: 3.725835/3.725835 = 1
N: 3.72857/3.725835 = 1
H: 7.53/3.725835 = 2
Therefore, the empirical formula is BNH₂.
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