The sample contains both Fe and oxygen
The mass of the sample is 36 g
28 g are Fe and 8 g are O
So to find the percent composition we can calculate using the following formula
Percent composition of the element = mass of the element / mass of the sample x 100%
Percent composition of Fe = 28 g / 36 g x 100 % = 77.8%
Percent composition of O = 8 g / 36 g x 100 % = 22.2%
Answer:
Find It Myself, Ask the Community, Get Live Help
Explanation:
The three main options for Microsoft users are Find It Myself, Ask the Community, Get Live Help. The first of which is finding it yourself through the search menu or help guidelines provided by Microsoft in all of their operating systems. Secondly, would be asking the community through search engines such as Google or through Microsoft help forums. Lastly, would be getting live help since Microsoft opertaing systems have a remote desktop feature that allows you to connect to another IT professional from a distance, or you can simply contact an IT professional to visit you in person for technical assistance.
Answer: 0.635 M
Explanation:
Molarity : It is defined as the number of moles of solute present per liter of the solution.
Formula used :
where,
n= Moles=
= volume of solution = 150 ml
as 1 mole of 
gives 3 moles of 
ions
Thus molarity of = 
Molarity of = 0.635 M
