Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
Answer:
to show that atoms are conserved in chemical reactions
Explanation:
We determine the percent by mass of water in the compound by dividing the mass of water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g.
percent by mass of water = (180 / 322)*(100 %) = 55.9%
The branch of chemistry that the chemist might use will be the branch of <em>organic chemistry</em>. This is because gasoline is an organic compound. We can say that a compound is organic if it contains a carbon atom. Gasoline is composed of long chains of alkanes (hydrocarbons with single bonds) ranging from 4 carbon atoms to 12 carbon atoms.
Answer:
The molarity of methylene blue is 1.5 × 10⁻⁵ M
Explanation:
When we talk about aqueous solutions, 1 ppm means 1 mg of solute per liter of solution. We need to express this concentration in molarity, which is moles of solute per liter of solution. To convert mass to moles we need the molar mass of methylene blue(MB), which is 320 g/mol.
Then,
