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IgorLugansk [536]
4 years ago
6

What is the majority of 0.50 g of na dissolved in a 1.5 L solution

Chemistry
1 answer:
Oxana [17]4 years ago
8 0

The correct answer is 0.014467 M.  

Molarity is defined as the number of moles present in a liter solution, that is, number of moles / liter solution.  

The molar mass of sodium (Na) is 23.0 g/mol

Thus, 1 mole of Na contains 23.0 g

Now, x moles of Na contains 0.50 g

Moles = 0.50 × 1 / 23.0

Moles = 0.50 / 23.0  

= 0.0217 moles of Na

Molarity = Number of moles / liters of solution

= 0.0217 / 1.5

= 0.014467 M


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Answer:

Electron microscopes differ from light microscopes in that they produce an image of a specimen by using a beam of electrons rather than a beam of light. Electrons have much a shorter wavelength than visible light, and this allows electron microscopes to produce higher-resolution images than standard light microscopes.

Explanation:

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3 years ago
What is the difference between “mass number” and “atomic mass”? which is found on the periodic table?
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4 0
3 years ago
One lap of an engineered hamster track measures 255 cm. To run 10. meters, how many laps should the hamster run? Report your ans
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3.9 laps

Explanation:

Step 1: Given data

Length of the hamster track (L): 255 cm

Total distance to be run (D): 10 m

Step 2: Convert "D" to centimeters

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10 m × (100 cm/1 m) = 1.0 × 10³ cm

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4 0
3 years ago
Find the number of moles of water that can be formed if you have 154 mol of hydrogen gas and 72 mol of oxygen gas.
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Answer:

77

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3 years ago
Which ligand binds tightest? ligand A, with a dissociation constant ( Kd ) of 10−9 M ligand D, with a percent occupancy of 80% a
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Answer:

The answer will be Ligand A with a dissociation constant (Kd) of 10^{-9}M

Explanation:

When the dissociation constant in the ligand is small (in order of nano) ( 10^{-9}) it will be more tied. Due to a dissociation constant measures how much a ligand can be able to be separated from the protein so if the number is small it means that the ligand is highly binded to the protein.

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3 years ago
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