Answer:
2.73%
Explanation:
Molarity of NaOH = 0.75 M
Density of solution = 1.1 g/mL
Mass percent of NaOH = ?
Solution:
Number of moles of NaOH = 0.75 mol from 0.75 mol/L
Mass of NaOH = number of moles × molar mass
Mass of NaOH = 0.75 mol × 40 g/mol
Mass of NaOH = 30 g
Mass of solution:
d = m/v
1.1 g/ mL = m/ 1000 mL
m = 1100 g
Percentage of NaOH:
% NaOH = mass of solute / mass of solution × 100
% NaOH = 30 g/ 1100 g × 100
% NaOH = 2.73%
Zero on a pH scale is very A. acidic, and 14 on a pH scale is very basic.
The lower the number on the scale, the more acidic it is.
<u>Answer:</u> The molar concentration of ammonia is 3.008 M
<u>Explanation:</u>
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is 
We are given:
Putting values in above equation, we get:
Hence, the molar concentration of ammonia is 3.008 M
