He then split the list of elements into several columns so that elements beside each other had similar ?

Chemistry

1 answer:

kodGreya [7K]3 years ago

3 0

Answer:

Properties

Explanation:

Mendeleev realized that the physical and chemical properties of elements were related to their atomic mass in a 'periodic' way, and arranged them so that groups of elements with similar properties fell into vertical columns in his table.

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A weak acid is one which:

aleksklad [387]

It bbbbbbbbbbbbbbbbbb

8 0

3 years ago

2.7g of aluminum metal is placed into 200g of

ICE Princess25 [194]

Answer:

2Al + 6HCl--> 2AlCl3 + 3H2

take the atomic mass of Al =27.0, Cl = 35.5, and H= 1.0,

no. of moles = .mass / molar mass

no. of moles of Al placed = 2.7 / 27.0

=0.1 mol

Assuming Al is limiting (because the concentration nor volume of HCl solution is given).

From the equation, the mole ratio of Al : AlCl3 = 2:2 = 1: 1,

meaning for each 1 mole of Al reacted, it gives out 1 mole of AlCl3. This also means the no. of moles of Al reacted equals to the no. of moles of AlCl3 produced, which is 0.1 mole.

mass = no. of moles x molar mass

hence,

mass of AlCl3 produced = 0.1 / (27 + 35.5x3)

= 0.00075 g

c. since this question is unclear, and the concentration nor volume of HCl solution is given, part c cannot be answered. Please let me know if you have any more info regarding it! thanks :)

d. From the equation, the mole ratio of Al:H2 = 2:3, meaning every 2 moles of Al reacted, gives out 3 moles of hydrogen.

using this ratio, no. of moles of H2 produced will = 0.1 x 3 / 2

=0.15 mol

At STP, the molar volume of gas is 22.4 dm3 mol-1,

volume = no. of moles x molar volume

hence volume of H2 obtained = 0.15 x 22.4

= 3.36 dm3

6 0

4 years ago

g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut

Elden [556K]

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) + copper carbonate(s)

The balanced chemical equation of the reaction is:

$CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)$