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3 years ago

What is the length of XY

Mathematics

2 answers:

Semenov [28]3 years ago

8 0

Answer:

The length of XY is 35.

Step-by-step explanation:

Since triangle FGH is similar to triangle XYZ, that means their sides are proportional to each other. FH corresponds to XZ, GH corresponds to YZ, and FG corresponds to XY. When dividing the corresponding length of triangle XYZ to the corresponding sides of triangle FGH, both $\frac{10}{4}$ and $\frac{40}{16}$ equals 2.5, so the side XY divided by 14 will also equal 2.5. To find the length of XY, multiply 14 by 2.5 and you'll get that the length of side XY is equal to 35.

raketka [301]3 years ago

6 0

I answered C for that question.

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What us 1/10 of 3,000

s344n2d4d5 [400]

1/10 of 3,000 is 300. Just divide by 10 to get the answer

5 0

3 years ago

Describe and correct the error in writing an equation of the line shown

Rudiy27

Answer:

$y = -\frac{3}{5}x+4$

Step-by-step explanation:

Given:

$(x_1,y_1) = (0,4)$

$(x_2,y_2) = (5,1)$

The attachment completes the question

From the attachment, the slope of the line was calculated as:

$m = \frac{1-4}{0-5}$

This step is inaccurate because the slope of a line is calculated using

$m = \frac{y_2-y_1}{x_2-x_1}$

Which gives

$m = \frac{1-4}{5-0}$

$m = \frac{-3}{5}$

$m = -\frac{3}{5}$

The line equation is then calculated using:

$y -y_1 = m(x - x_1)$

Substitute values for m, x1 and y1

$y - 4 = -\frac{3}{5}(x - 0)$

$y - 4 = -\frac{3}{5}(x)$

Open bracket

$y - 4 = -\frac{3}{5}x$

Make y the subject

$y = -\frac{3}{5}x+4$

6 0

3 years ago

If angle a has the terminal ray that falls in the fourth quadrant and cosine a equals 5/9 then determine the value of sin a in s

Tema [17]

Answer: $-\dfrac{2\sqrt{14}}{9}$

Step-by-step explanation:

Given

$\cos a=\dfrac{5}{9}$

$a$ lies in the fourth quadrant

So, sine must be negative in the fourth quadrant

Using identity $\sin ^2 x+\cos^2 x=1$ to find sine value

$\Rightarrow \sin^2 a=1-\dfrac{5^2}{9^2}$

$\\\\\Rightarrow \sin^2 a=1-\dfrac{25}{81}\\\\\\\Rightarrow \sin^2 a=\dfrac{56}{81}\\\\\\\Rightarrow \sin a=-\sqrt{\dfrac{56}{81}}\\\\\\\Rightarrow \sin a=-\dfrac{2\sqrt{14}}{9}$