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Ede4ka [16]
3 years ago
9

Need help please omg Perform each of the following conversions being sure to set up the appropriate conversion factor in each ca

se 59. a. 12.5 in to centimeters c. 2513ft to miles 60. a. 2.23m to yards. c. 292cm to inches Please show work
Chemistry
1 answer:
sertanlavr [38]3 years ago
6 0

Answer:

The answer to your question is:

a) 31.75 cm

b) 0.475 miles

c) 2.44 yards

d) 11496.04 inches

Explanation:

Convert

a)           12.5 in to cm

         1 in ------------------- 2.54 cm

       12.5 in ----------------    x

            x = 12.5(2.54)/1 = 31.75/ = 31.75 cm

b)          2513 ft to miles

           1 mile -------------- 5280 ft

           x miles ------------ 2513 ft

        x = 2513(1)/5280 = 0.475 miles

c) 2.23 m to yards

              1 m -------------   1,094 yards

            2.23 m ----------     x

       x= 2.23x1.094/1 = 2.44 yards

d)  292 m to inches

            1 m ---------------- 39.37 inches

          292 m -------------     x

    x = 292 x 39.37/1 = 11496.04 inches

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Elena-2011 [213]

Answer:

Volume occupied by  Neon gas is 52.67 L

Explanation:

Using Ideal Gas Equation:

PV = nRT

where

P = pressure exerted by the gas = 57 atm

V = volume occupied = ?

n = number of moles = 115 moles

R = Ideal gas constant = 0.0821 L.atm/K.mol

(R value should be taken according to the units of Temperature,pressure, volume and mole)

T = Temperature = 45 + 273 = 318 K

(For temperature conversion from C to K add 273 to temperature:T + 273)

PV = nRT , So

V = \frac{nRT}{P}

Put values of T,P,n,R

V = \frac{115\times 0.0821\times 318}{57}

V = \frac{3002.39}{57}

V = 52.67 L

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6 0
4 years ago
(True or
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3 0
3 years ago
How many moles of water are represented by 8.33×10^18 molecules of water​
DENIUS [597]

Answer:

number of moles of water (n) = 1.383 x10 ⁻⁵ mol

Explanation:

Data Given:

No. of molecules of water =  8.33×10¹⁸

No. of Mole of water = ?

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So the formula could be written as

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Put the values in above formula

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                  no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³

                  no. of moles (n) = 1.383 x10 ⁻⁵

so  1.383 x10 ⁻⁵ moles of water are represented by  8.33×10¹⁸ molecules of water.

   

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3 years ago
What is the mass number of an ion with 107 electrons, 157 neutrons, and a 1 charge?
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