Answer:
Explanation:
on volleyballit's clockwise and What Would Happen If Someone Served Out Of Order? If the wrong player on your team serves because it's not their turn, the point and the possession of the serve will go to your opponents.
Answer:
Explanation:
mass of displaced oil = 11 x .9
= 9.9 gm
9.9 x 10⁻³ kg
weight of displaced oil = 9.9 x 9.81 x 10⁻³ N
= .097 N .
buoyant force by oil = .097 N
weight of unknown metal = .1 x 9.8
= .98 N .
weight of metal in oil = .98 - .097
= .883 N .
=
The correct answer is going to be <span>C, because in the nucleus of an atom there are protons and electrons; which can't move, and are surrounded by electrons on the electrical cloud</span>
Answer:
(a) f= 622.79 Hz
(b) f= 578.82 Hz
Explanation:
Given Data
Frequency= 600 Hz
Distance=1.0 m
n=120 rpm
Temperature =20 degree
Before solve this problem we need to find The sound generator moves on a circular with tangential velocity
So
Speed of sound is given by
c = √(γ·R·T/M)
............in an ideal gas
where γ heat capacity ratio
R universal gas constant
T absolute temperature
M molar mass
The speed of sound at 20°C is
c = √(1.40 ×8.314472J/molK ×293.15K / 0.0289645kg/mol)
c= 343.24m/s
The sound moves on a circular with tangential velocity
vt = ω·r.................where
ω=2·π·n
vt= 2·π·n·r
vt= 2·π · 120min⁻¹ · 1m
vt= 753.6 m/min
convert m/min to m/sec
vt= 12.56 m/s
Part A
For maximum frequency is observed
v = vt
f = f₀/(1 - vt/c )
f= 600Hz / (1 - (12.56m/s / 343.24m/s) )
f= 622.789 Hz
Part B
For minimum frequency is observed
v = -vt
f = f₀/(1 + vt/c )
f= 600Hz / (1 + (12.56m/s / 343.24m/s) )
f= 578.82 Hz
Answer:
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²
Explanation:
Hi there!
The acceleration is defined as the change in velocity in a time:
a = Δv / Δt
Where:
a = acceleration.
Δv = change in velocity = final velocity - initial velocity.
Δt = elapsed time.
In this case:
Initial velocity = 60 mi/h
final velocity = 50 mi/h
elapsed time = 3.0 s
Let´s convert the time unit into h:
3.0 s · 1 h /3600 s = 1/1200 h
Now, let´s calculate the acceleration:
a = Δv / Δt
a = (50 mi/h - 60 mi/h) / 1/1200 h
a = -1.2 × 10⁴ mi/h²
The magnitude of the acceleration is 1.2 × 10⁴ mi/h²