Answer: g^36
Step-by-step explanation:
The absolute value is always non-negative!
So the absolute value of 57 is 57 itself, as it's non-negative (i.e. it's positive or 0).
Opposite value is the number with a different sign: an opposite value of a positive number is negative, so here it will be -57 .
The correct answer is C.
9514 1404 393
Answer:
- 0 < x < 4
- (- ∞ < x < 0) ∪ (4 < x < ∞)
- x ∈ {0, 4}
Step-by-step explanation:
1. The solution is the set of x-values for which the graph is above the x-axis, where y = 0. Those x-values are in the interval (0, 4).
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2. The solution is the set of x-values for which the graph is below the x-axis. Those x-values are in either of the two intervals (-∞, 0) or (4, ∞).
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3. The x-intercepts of the graph are x=0 or x=4.
Answer: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
Step-by-step explanation: A= s^2 <- for a square
A= 1/2*b*h <- for a triangle
A= 4^2= 16
A= 1/2*8*6 (The whole height is 8 yd)
A= 1/2*48
A= 24
24+16= 40 yd^2
"B" is the answer.
I hope this helps!
Remark
The way you have to set this up is to take the new number for the males and put it over the total for the males and females. The new number for the males / total = 3/5.
Step One
Find the total number of females
100 + 160 = 260 when 100 females have been added to the study.
Step Two
Find the number of males
The total number of males = 240 + x where x is the number of males to be added.
Step Three
Find the total for both
260 + 240 + x = Total
500 + x = Total.
Step Four
Find the ratio of males to total
(240 + x) / (500 + x) = 3/5
Step Five
Cross multiply and solve
(240 + x)*5 = (500+x)*3
1200 + 5x = 1500 + 3x Subtract 1200 from both sides.
5x = 1500 - 1200 + 3x
5x = 300 + 3x Subtract 3x from both sides.
5x - 3x = 300
2x = 300 Divide by 2
x = 300 / 2
x = 150
Check
(240 + 150 ) / (500 + 150) = ? 3/5
390 / 650 = ? 3/5
39/65 = ? 3/5 Divide the top and bottom on the left by 13
3/5 = 3/5 and it checks.
