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suter [353]
3 years ago
9

Please help me I've been stuck on this since the morning. I keep texting my friend to help me but she won't answer me she just l

eaves me on read. please​

Mathematics
1 answer:
yan [13]3 years ago
4 0

Answer:

sounds like a relationship problem

Step-by-step explanation:

that cheating wont fix.

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Determine algebraically whether the function is even, odd, or neither even nor odd.
m_a_m_a [10]
For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x)  [No Relation]

(-x)^n = x^n   for n -> even
(-x)^n = -x^n  for n -> odd
In your example:

f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1  ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x   (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x)  [between the bracket was the original fn]

f(x) = - f(-x)   
so the function is odd also called symmetric about the origin
7 0
3 years ago
I Need Help Answer Plz I Need It Badly!!!
salantis [7]

Answer: Yes it is.

Step-by-step explanation: So we are already told that segment AC is congruent to segment DC. They both have a right angle, as indicated by the angle symbol, and they share side-length BC.

According to the Hypotenuse-Leg Theorem, two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles. AC and DC are hypotenuses and they are congruent. And BC, the shared side, is a corresponding congruent leg. And since they are both right triangles, we then know that the HL Theorem applies.

3 0
2 years ago
Which is equivalent to square root 10st x square root 15tu
aivan3 [116]

\sqrt{10st}\cdot\sqrt{15tu}=\sqrt{10st\cdot15tu}=\sqrt{150st^{2}u}=\sqrt{25\cdot6\cdot st^{2}u} =   \\\\= \sqrt{5^{2} \cdot t^{2}\cdot6 \cdot su}=5t\sqrt{6su}

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3 years ago
Which is the graph of f(x) = 0.5(4)?
Llana [10]

Answer:an line thats not straight

Step-by-step explanation:

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3 years ago
Estimate the solution to the following system of equations by graphing.
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3 0
3 years ago
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