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myrzilka [38]
3 years ago
9

At the local pet store, zebra fish cost $2.05 each and neon tetras cost $2.30 each. If Sameer

Mathematics
1 answer:
Tasya [4]3 years ago
7 0

Answer:

7

Step-by-step explanation:

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Solve: -(1/4)m + 5 = 16
liq [111]

Answer:

m=-44

Explanation: distribute the negative and add -1/4 to m and then take the 5 away from 16 and then multiply both sides

3 0
3 years ago
Read 2 more answers
Integrate this two questions ​
tankabanditka [31]

Simplify the integrands by polynomial division.

\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)

\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)

Now computing the integrals is trivial.

5.

\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}

where we use the power rule,

\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)

and a substitution to integrate the last term,

\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)

8.

\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}

using the same approach as above.

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1 year ago
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slava [35]

Answer:

What shape is the object in question?

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Mrs. Jordan participates in a math contest. She completes each question in 1/2
marysya [2.9K]

it takes mrs. jordan 24 minutes to complete 12 questions.

if she completes each question in 1/2 a minute, then:

1/2 / 12 questions = 24 minutes.

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3 years ago
A GPA is usually an example of a.
Ann [662]
The answer is grade point average (GPA)
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2 years ago
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