With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)
It woulds be x+15 because if you take 2x and subtracted from the 3x then you get x and then you add the 9 and 6 witch you get 15
-2.964 Your welcomeeeeeeeee
Step-by-step explanation:
The Answer for the above question is
The four integers are 1,2,5,10. And Sum of the four integers is 18 .
<u>Method : </u>
Product of four different positive integers is 100 .
<u>First</u> of all lets break the number "100"
⇒ 100 = 50*2
⇒ 100 = 25 * 2 * 2
⇒ 100 = 5 * 5 * 2 * 2
But here we get the same integers 2 and 5 and we want different positive integers . So hereby merge 5 * 2 which is 10.
Let's get to the possible combination -
After merging 5*2 = 10 we get the answer as -
⇒ 100 = 1 * 2 * 5 * 10
Here, we have 1, 2, 5, 10. these are the positive integers whose product gives 100 .
Sum of these products is -
⇒ Sum = 1 + 2 + 5 + 10
⇒ Sum = 18 .
Sum of these four Integers is 18.
Answer:
b
Step-by-step explanation:
