Hey my guy the answer is C. 5 I had the same question awhile back
here two forces are acting at different angles and we need to find its resultant
forces are given as
@125 degree
@200 degree
now in order to find its resultant we will find its components
here it is given as
![F_{1x} = 550 cos125 = -315 N](https://tex.z-dn.net/?f=F_%7B1x%7D%20%3D%20550%20cos125%20%3D%20-315%20N)
![F_{1y} = 550sin125 = 450.5 N](https://tex.z-dn.net/?f=F_%7B1y%7D%20%3D%20550sin125%20%3D%20450.5%20N)
![F_{2x} = 600 cos200 = -563.8 N](https://tex.z-dn.net/?f=F_%7B2x%7D%20%3D%20600%20cos200%20%3D%20-563.8%20N)
![F_{2y} = 550sin200 = -188.11 N](https://tex.z-dn.net/?f=F_%7B2y%7D%20%3D%20550sin200%20%3D%20-188.11%20N)
Now net force in x and y direction is given as
![F_x = -315 -563.8 = - 878.8 N](https://tex.z-dn.net/?f=F_x%20%3D%20-315%20-563.8%20%3D%20-%20878.8%20N)
![F_y = 450.5 - 188.11 = 262.4 N](https://tex.z-dn.net/?f=F_y%20%3D%20450.5%20-%20188.11%20%3D%20262.4%20N)
so net force is given as
![F = -878.8 \hat i + 262.4 \hat j](https://tex.z-dn.net/?f=F%20%3D%20-878.8%20%5Chat%20i%20%2B%20262.4%20%5Chat%20j)
now the magnitude is given as
![F = \sqrt{878.8^2 + 262.4^2}](https://tex.z-dn.net/?f=F%20%3D%20%5Csqrt%7B878.8%5E2%20%2B%20262.4%5E2%7D)
![F = 917.13 N](https://tex.z-dn.net/?f=F%20%3D%20917.13%20N)
angle of the force is given as
![\theta = tan^{-1}\frac{F_y}{F_x}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7BF_y%7D%7BF_x%7D)
![\theta = tan^{-1}\frac{262.4}{-878.8}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%5Cfrac%7B262.4%7D%7B-878.8%7D)
![\theta = 163.4^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20163.4%5E0)
so net resultant force is 917.13 N at 163.4 degree
Answer:
I guess the answer is charging by friction
Answer:
A smooth, possibly curved line that you judge to come closest to all the points i.e, best fit line.
Explanation:
Line of best fit is a line through a plot of data points that best expresses the relationship between those points. The statement <em>'A smooth, possibly curved line that you judge to come closest to all the points'</em> defines the best fit line.
The other options are incorrect because we do not represent the plot of data points by horizontal or vertical lines representing their average/ midpoint values.