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3 years ago

6

An elevator accelerates from rest to a velocity of 12.0 m/sec as it rises 28.0 meters. What was its’ acceleration, and for what

time did it travel while it was accelerating?

1 answer:

Dafna11 [192]3 years ago

4 0

Answer:

given that

V = 12.0 m/s

U = 0 m/s

s = 28 m

Explanation:

using the equation of motion

V^2 = U^2 + 2as

12^2 = 0 + 2(28)a

144 = 56a

a = 5.5 m/s^2

v = u +at

12 = 0 + 5.5t

12 = 5.5t

t = 2.2s

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