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Vesna [10]
3 years ago
13

Within an internal combustion engine, the can-shaped component that moves up and down the cylinder

Physics
1 answer:
Mrrafil [7]3 years ago
6 0


This component is called the piston.

A piston is a cylindrical engine component that slides back and fourth in the cylinder bore by forces produced during the combustion process. The piston acts as a movable end of the combustion  chamber.

Pistons are commonly made of a cast aluminum alloy for excellent and light weight thermal conductivity. Aluminum expands when heated and proper clearance must be provided to maintain  free piston movement in the cylinder.

If the clearance is not sufficient the piston will seize and if it is excessive there will be loss of compression.

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state and explain any effect on sensitivity of liquid in a glass thermometer (i) reducing the diameter of capillary tube​
Ad libitum [116K]

Answer:

please give me brainlist and follow

Explanation:

The measuring sensitivity of liquid-in-glass thermometers increases with the amount of liquid in the thermometer. The more liquid there is, the more liquid will expand and rise in the glass tube. For this reason, liquid thermometers have a reservoir to increase the amount of liquid in the thermometer.

4 0
3 years ago
The device used to measure a masses of a body is kilogram . true or false​
olga nikolaevna [1]

Answer: false

Explanation:

While kilograms are the unit used to measure body mass, the device used is a scale.

Hope it helps :)

6 0
3 years ago
A piston-cylinder device initially contains 0.3 kg of nitrogen gas at 160 kPa and 140oC. The nitrogen is now expanded isothermal
irakobra [83]

Answer:

<h2>Work done by the gas is given as</h2><h2>W = 1.72 \times 10^4 J</h2>

Explanation:

As we know that the process is isothermal so here work done is given as

W = nRTln(\frac{P_1}{P_2})

here we know that

n = \frac{w}{M}

n = \frac{300}{28} = 10.7 moles

now we have

W = 10.7 (8.31)(273 + 140) ln(\frac{160}{100})

so we have

W = 1.72 \times 10^4 J

4 0
3 years ago
dopasuj wartości pracy z ramki do przedstawionych sytuacji ,a nastepnie wyraż te prace w dżulach uwaga jedna wartośc pracy nie b
Eduardwww [97]

Answer:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Explanation:

Całą część pytania można znaleźć na poniższym schemacie.

Z diagramu załączonego poniżej; mamy

A - samolot lotniczy

B - dźwig

C - podnoszenie ciężarów

Wszyscy to wiemy ;

1kJ = 1000 J

1MJ = 1000000 J

Mamy cztery opcje; i.e 200 MJ, 800 kJ, 1.6 kJ  and 250 mJ

Z czterech opcji można wykluczyć 250 mJ, ponieważ jest to 0,25 J, co przedstawia bardzo niską energię w porównaniu z trzema warunkami pokazanymi na schemacie.

Więc:

A (samolot) - 200 MJ = 200000000 J

B (dźwig) - 800 kJ = 800000 J

C (podnośnik)-1.6 kJ = 1600 J

Największą pracę wykona samolot. Jest tak, ponieważ ma bardzo dużą masę i bardzo dużą prędkość. W związku z tym istnieje potrzeba wytworzenia ogromnej ilości ciepła i energii.

Z drugiej strony żuraw może podnieść ładunek o wiele większy i przewyższa ciężar ciężaru, więc praca wykonywana przez dźwig musi być zdecydowanie większa niż praca ciężarka.

3 0
3 years ago
What is three pieces of evidence of the big bang theory?
Hoochie [10]
The radiation that was emitted is still "visible"

The universe is still expanding

Dark matter could only be crated by an atomic collapse big enough to create or destroy a universe
4 0
3 years ago
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