Within an internal combustion engine, the can-shaped component that moves up and down the cylinder

Physics

1 answer:

Mrrafil [7]3 years ago

6 0

This component is called the piston.

A piston is a cylindrical engine component that slides back and fourth in the cylinder bore by forces produced during the combustion process. The piston acts as a movable end of the combustion chamber.

Pistons are commonly made of a cast aluminum alloy for excellent and light weight thermal conductivity. Aluminum expands when heated and proper clearance must be provided to maintain free piston movement in the cylinder.

If the clearance is not sufficient the piston will seize and if it is excessive there will be loss of compression.

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Read 2 more answers

A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When

katovenus [111]

The temperature of the air in the open orang pipe has been altered by 18.73° C

The frequency of an open orang pipe is estimated by using the formula:

$\mathbf{f = \dfrac{v}{2L}}$

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

$\mathbf{254 - \dfrac{v}{2L} }$

These combinations of frequency produce 4 beats per sound.

i.e.

$\mathbf{254 - \dfrac{v}{2L} =4}$

$\mathbf{ \dfrac{v}{2L} = 254-4 }$

$\mathbf{ \dfrac{v}{2L} = 250 ----(1)}$

When it is altered, the beats first diminish and increase again by 4.

i.e.

$\mathbf{ \dfrac{v'}{2L} = 254+4 }$

$\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }$

If we equate both equations (1) and (2) together, we have:

$\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}$

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.

Hence;