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ss7ja [257]
3 years ago
6

What is the differential equation governing the growth of current in the circuit as a function of time after t=0? express the ri

ght-hand side of the differential equation for di(t)dt in terms of i(t), vb, r, and l?
Physics
1 answer:
Reika [66]3 years ago
3 0

Answer:

v_{b}=ir+L\frac{di}{dt}

Explanation:

A differential equation that contain a term with di(t)/dt is in a RL circuit. Here we have

v_{b}=v_{r}+v_{i}

where vr is the voltage in the resistance, vi is the voltage in the inductance and vb is the source voltage. But also we have that

v_{r}=ir\\v_{i}=L\frac{di}{dt}

where L is the inductance of the circuit, r is the resistance an i is the current. By replacing we have the differential equation

v_{b}=ir+L\frac{di}{dt}

I hope this is useful for you

regards

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The maximum range of projectle is R° if projected at angle of 45°. It'll be 300% of Range of projectile if projected at angle? a
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Answer:

The maximum range is 300% of the range of the projectile is projected at an angle of 9.74°.

None of the options are correct.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance travelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile

θ = angle above the horizontal at which the projectile was launched

g = acceleration due to gravity = 9.8 m/s²

The range is maximum when θ = 45°

R when θ = 45° is

R = (u² sin 90°)/g = (u²/g)

We are then told that this maximum range is 300% of the value obtainable for the range at a particular angle

Maximum range = 3R

(u²/g) = 3(u² sin 2θ)/g

Sin 2θ = (1/3)

2θ = sin⁻¹ (1/3) = 19.47°

θ = (19.47°/2) = 9.74°

Hope this Helps!!!

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Hello!

Use the <u>second law of Newton:</u>

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Resolving:

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