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3 years ago

What happens to the charge if a nonmetal takes two valence electrons?

Chemistry

2 answers:

spin [16.1K]3 years ago

6 0

Answer:

The nonmetal will gain a negative charge of magnitude 2

Explanation:

X be the nonmetal

On gaining two electrons

X^2-

Serga [27]3 years ago

3 0

Answer:

if a non-metal takes two valence electrons then it get negatively charged to form ion.

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You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed d

Inga [223]

Answer:

You need 375 mL of BaCl2 solution.

Explanation:

M1V1=M2V2

Dilution formula. Substitute known values and solve for V1.

M1 = 2.0 M

M2 = 1.50 M

V2 = 500 mL

(2.0 M)(V1) = (1.50 M)(500 mL)

V1 = (1.50 M)(500 mL) / (2.0 M)

V1 = 375 mL

7 0

2 years ago

4. How many grams of ammonium carbonate are needed to decompose in order to produce

Thepotemich [5.8K]

Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0

3 years ago

1. The emission spectrum of mercury atoms has a bright green line with wavelength

SashulF [63]

Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.

From the formula;

E = hc/λ

h = Plank's constant = $6.6 * 10^-34$ Js

c = speed of light= $3 * 10^8$

λ = wavelength = $546.1 * 10^-9$ m

E = $6.6 * 10^-34 * 3 * 10^8/546.1 * 10^-9$

E = $3.63 * 10^-19$ J

Also;

E =hf

Where;

h = Planks's constant

f = frequency of photon

f = E/h

f = $3.63 * 10^-19 J/6.6 * 10^-34$

f = $5.5 * 10^14$ Hz

Learn more: brainly.com/question/18415575

5 0

2 years ago

If the density of water is 1g/ml, what is the mass of 254ml of water?

Mariulka [41]

The mass of 254 mL of water is 254 g. Since the density of water is 1g/mL, we can simply multiply the density 1g/mL by 254 mL of water and get 254 g as our answer. Since mL is in the numerator and denominator, mL cancels out and we are left with g only.

8 0

3 years ago

What is the value for ∆Soreaction for the following reaction, given the standard entropy values? 2H2S(g) + SO2(g) 3Srhombic(s) +

Mademuasel [1]

Answer: $\Delta S^{0}$ for the reaction is -186.75 J/K

Explanation:

Change in entropy ( $\Delta S^{0}$ ) for the given reaction under standard condition is given by-

$\Delta S^{0}$ = $[3\times S_{rhombic}^{0}_{(s)}]+[2\times S_{H_{2}O}^{0}_{(g)}]-[2\times S_{H_{2}S}^{0}_{(g)}]-[1\times S_{SO_{2}}^{0}_{(g)}]$

So $\Delta S^{0}$ = $[3\times 31.8 J/K.mol]+[2\times 188.825 J/K.mol]-[2\times 205.79 J/K.mol]-[1\times 248.22 J/K.mol]$ = -186.75 J/K

5 0

2 years ago