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fgiga [73]
3 years ago
13

The atria beat prior to the ventricles. What purpose does this serve?

Chemistry
1 answer:
Zarrin [17]3 years ago
4 0

Answer:

The atria and ventricles work together, alternately contracting and relaxing to pump blood through your heart. The electrical system of your heart is the power source that makes this possible.

Your heartbeat is triggered by electrical impulses that travel down a special pathway through your heart:

Explanation:

Hope this helps

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Hsgsfqg hsagdjhagsydt ahsgdytratdw
stiks02 [169]

Answer:

Yes

Explanation:

3 0
2 years ago
Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p
UNO [17]

Answer : The equilibrium constant K_c for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of Br_2.

\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}

\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M

Now we have to calculate the dissociated concentration of Br_2.

The balanced equilibrium reaction is,

                              Br_2(g)\rightleftharpoons 2Br(aq)

Initial conc.         1.731 M      0

At eqm. conc.      (1.731-x)    (2x) M

As we are given,

The percent of dissociation of Br_2 = \alpha = 1.2 %

So, the dissociate concentration of Br_2 = C\alpha=1.731M\times \frac{1.2}{100}=0.2077M

The value of x = 0.2077 M

Now we have to calculate the concentration of Br_2\text{ and }Br at equilibrium.

Concentration of Br_2 = 1.731 - x  = 1.731 - 0.2077 = 1.5233 M

Concentration of Br = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

K_c=\frac{[Br]^2}{[Br_2]}

Now put all the values in this expression, we get :

K_c=\frac{(0.4154)^2}{1.5233}=0.1133

Therefore, the equilibrium constant K_c for the reaction is, 0.1133

7 0
3 years ago
60 kg of fuel was completely burnt for an experiment. The amount of heat energy was found to be 180000KJ. Calculate calorific va
FrozenT [24]

Answer:

3000 kJ/kg

Explanation:

The calorific value of a substance is the amount of heat produced per unit mass by the combustion of the substance.

It is given by:

C=\frac{Q}{m}

where

Q is the amount of heat released

m is the mass of the fuel

In this problem, we have:

m = 60 kg is the mass of fuel

Q=180,000 kJ is the amount of heat released

Therefore, the calorific value of the fuel is:

C=\frac{180,000}{60}=3000 kJ/kg

6 0
3 years ago
Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
Gre4nikov [31]
2.43 kilograms is equal to 2430 grams because 1 kilogram is equal to 1000 grams.
4 0
3 years ago
Read 2 more answers
Which of the following describes the arrangement of valence electrons in a bond between H and F?
Sloan [31]
C; The Valence electrons spend more time around the atom of F
6 0
3 years ago
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