Answer:
D)
Explanation:
seems like the most logical option out of all listed.
Answer:
1) Increasing the pressure A) Shift to the left
2) Removing hydrogen gas B) Shift to the right
3) Adding a catalyst C) No effect
Explanation:
- <em>Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>
<em></em>
<u><em>1) Decreasing the pressure:</em></u>
- When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
- The reactants side (left) has 4.0 moles of gases and the products side (right) has 2.0 moles of gases.
- So, decreasing the pressure will shift the reaction to the side with more moles of gas (left side).
<u><em>so, the right match is: A) Shift to the left.</em></u>
<em><u>2) Adding hydrogen gas:</u></em>
- Adding hydrogen gas will increase the concentration of the reactants side, so the reaction will be shifted to the right side to suppress the increase in the concentration of hydrogen gas by addition.
<u><em>so, the right match is: B) Shift to the right.</em></u>
<u><em></em></u>
<u><em>3) Adding a catalyst:</em></u>
- Catalyst increases the rate of the reaction without affecting the equilibrium position.
- Catalyst increases the rate via lowering the activation energy of the reaction.
- This can occur via passing the reaction in alternative pathway (changing the mechanism).
- The activation energy is the difference in potential energies between the reactants and transition state (for the forward reaction) and it is the difference in potential energies between the products and transition state (for the reverse reaction).
- in the presence of a catalyst, the activation energy is lowered by lowering the energy of the transition state, which is the rate-determining step, catalysts reduce the required energy of activation to allow a reaction to proceed and, in the case of a reversible reaction, reach equilibrium more rapidly.
- with adding a catalyst, both the forward and reverse reaction rates will speed up equally, which allowing the system to reach equilibrium faster.
<u><em>so, the right match is: B) No effect.</em></u>
<u><em></em></u>
When iron loses the 2 4s electrons, it attains a valency of +2. Sometimes, iron will also lose one of the paired electrons from 3d orbital, leaving the entire 3d orbital filled with unpaired electrons (which provides a more stable configuration). In this case, its valency will be +3.
Answer:
- The first equation, <em>a. PV = nRT</em>, <u>is not</u> <em>a valid statement of the ideal gas law.</em>
Explanation:
The basic expression for the<em> ideal gas law</em> is:
.......... [Equation 1]
Where:
- n is the number of moles of the gas
- V is the volume occupied by the gas
- p is the pressure exerted by the gas molecules
- T is the temperature in absolute scale (Kelvin)
- R is the Universal gas constant (0.0821 atm-liter /K-mol or the equivalents in other units)
You can perform different algebraic operations to obtain equivalent equations:
<u>Choice b) Divide equation 1 by T and you get</u>:
- pV / T = nR, which is the choice b. from your list.
<u>Choice c) Divide equation 1 by n × V and you get</u>:
- p/n = RT / V, which is the choice c. from your list.
<u>Choice d) Divide equation 1 n × T and you get</u>:
- pV / (nT) = R, which is the choice d. from your list.
The choice a. p = nRTV states that p and V are in direct relation, when the ideal gas law states that p and V are inversely related, so that equation is wrong.
<u>Conclusion: </u>the choice a, p = nRTV, is not a statement of the ideal gas law.
75mL=0.075L
Molarity=moles/Liters
Moles=0.075(3.50)
=0.2625
Since the number of moles never changes,
we know there are 0.2625moles (or 0.26) in the 12M HCl.
0.2625/12=0.021875L
(0.022L)
