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DedPeter [7]
3 years ago
10

Na CN + HCl ->?? Thanks for your time ​

Chemistry
1 answer:
Tom [10]3 years ago
4 0

Sodium chloride and prussic acid are formed

NaCN+HCl→NaCl+HCN

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Which of the following is an example of the biosphere interacting with the atmosphere? Question 11 options: a human breathing in
Mamont248 [21]

Answer:

The answer would be volcano adding ash to the air.

hope it helps!

8 0
3 years ago
Describe Rutherford’s gold foil experiment and how the experimental results led to specific changes in the accepted model of the
photoshop1234 [79]
Before Rutherford's discovery, the accepted atomic model was J. J Thompson's Plum Pudding Model. According to J.J Thompson, the atom is composed of negatively charged particles. They were then called 'corpuscles', but now known to be electrons. Outside of this atom, surrounds a cloud of positively charged electrons to balance out the charge of electrons, which makes the atom neutral. The 'plum' were the electrons, whereas the 'pudding' were the protons.

Through Rutherford's gold foil experiment, he disproved J.J Thompson's theory. Rutherford was very interested in studying the behavior of x-rays, which was then recently discovered by Curie. When he shot a beam of alpha particles (particles with 2 neutrons and 2 protons, or the Helium atom) toward the gold foil, the particles were deflected by a slight angle. He then theorized that these deflections were due to the existence of a dense nucleus inside the atom. 

Following Rutherford's discovery of the nucleus, Niels Bohr theorized the planetary model of the atomic structure. According to him, the atom is like a solar system wherein the Sun is the nucleus and the planets are the electrons orbiting around it. The electrons and protons move this way because they are influenced by an electric force due to the difference of their charges.
5 0
3 years ago
Pls help Which statement is true about the environment of urban areas?
wel

The correct answer is A. Urban areas have higher temperatures.

Explanation

Urban Area is a term to refer to cities. Urban areas are characterized by having a developed infrastructure (wide roads, vehicular bridges, wide platforms, tall buildings, residential areas, industrial areas, among others).

Recent studies affirm that urban areas are warmer than surrounding areas; This phenomenon is because the materials with are built buildings, roads, houses, and others, concentrate the sun's rays, increasing the temperature of cities. In addition, the lack of trees deepens this phenomenon, because the trees contribute to cooling by physicochemical processes such as evapotranspiration.

According to the above, it is possible to affirm that urban areas are hotter than their surrounding area because they lack vegetation, and the materials with which it is built contribute to the increase in temperature.

On the other hand, urban areas are characterized by habitat fragmentation, more problems with soil erosion, and less rain infiltration into the soil.

Learn more in: brainly.com/question/23587978

6 0
3 years ago
Avoid of diseases in monsoon season-
Dominik [7]

Answer:

Monsoon seasonal diseases can be avoided by keeping surroundings clean, removing stagnant water, eating homemade food, washing hands properly, eating clean and drinking boiled water.

Explanation:

1. Make efforts in making the environment mosquito free by proper cleaning and removing stagnant water as well.

2. Use mosquito repellant, mainly net that has no side effects and is ecofriendly.  

3. Avoid moving to crowded places to prevent viral infections.

4. Consume food made at home and boiled water.

5. Wash hands before consuming food.

4 0
3 years ago
A balloon contains 2.0 L of air at 101.5 kPa . You squeeze the balloon to a volume of 0.25 L.
8_murik_8 [283]
<h3>Answer:</h3>

812 kPa

<h3>Explanation:</h3>
  • According to Boyle's law pressure and volume of a fixed mass are inversely proportional at constant absolute temperature.
  • Mathematically, P\alpha \frac{1}{V}

At varying pressure and volume;

P1V1=P2V2

In this case;

Initial volume, V1 = 2.0 L

Initial pressure, P1 = 101.5 kPa

Final volume, V1 = 0.25 L

We are required to determine the new pressure;

P2=\frac{P1V1}{V2}

Replacing the known variables with the values;

P2=\frac{(101.5)(2.0L)}{0.25L}

           = 812 kPa

Thus, the pressure of air inside the balloon after squeezing is 812 kPa

8 0
3 years ago
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