1. What is the Density of an object with a mass of 46.0g and a volume of 2cc?

gayaneshka [121]

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WHAT IS KNOWN AS HYBRIDIZATION

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<h3> It is the change in the orbitals of the central atom of the molecule to form bonds with other atom if same type or another type.</h3>

The hybrid orbitals r of same level .

The Hybridization takes place in between orbitals of equal or very less energy levels to form same level of energy in all orbitals.

The orbitals combine is always equal to The number of orbitals formed

The names of hybridized orbitals r kept according to the orbital which r combined to form them

sp orbital :- one s and one p combine to form sp orbital

$s {p}^{2}$ orbital :- one s and two p orbitals combine to form it..

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4 0

2 years ago

Read 2 more answers

Water, H2O, is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to shared __________

adell [148]

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

<h3>What kinds of bonds exist?</h3>

Covalent bonds: These are formed between nonmetals and electrons by sharing electrons.
Ionic bonds: These are formed between metals, which lose electrons, and nonmetals, which gain electrons.
Metallic bonds: There are formed between metals. Electrons are delocalized in a cloud.

Water, H₂O, is a molecule made of 2 nonmetals: oxygen and hydrogen. The bonds that hold water molecules together are due to shared electrons, and known as covalent bonds.

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

Learn more about chemical bonds here: brainly.com/question/6071754

5 0

2 years ago

Th e enzyme-catalyzed conversion of a substrate at 25°C has a Michaelis constant of 0.045 mol dm−3. Th e rate of the reaction is

Elis [28]

Answer:

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

Explanation:

Michaelis–Menten 's equation:

$v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}$

$V_{max}=k_{cat}[E_o]$

v = rate of formation of products =

[S] = Concatenation of substrate

$[K_m]$ = Michaelis constant

$V_{max}$ = Maximum rate achieved

$k_{cat}$ = Catalytic rate of the system

$[E_o]$ = Initial concentration of enzyme

We have :

$K_m=0.045 mol/dm^3$

$v=1.15 mmol/dm^3 s=1.15\times 10^{-3} mol/dm^3 s$

$[S]=0.110 mol/dm^3$

$v=V_{max}\times \frac{[S]}{K_m+[S]}$

$1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}$

$V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s$

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

8 0

2 years ago

What is the pressure of nitrogen in atmospheres of a sample that is at 745 mmHg?

Semenov [28]

<span>The pressure of nitrogen in atmospheres of a sample that is at 745 mmHg- n2= .780 atm because 78 (from the 78%) 78/100=0.78.</span>

6 0

3 years ago

If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m

Nadusha1986 [10]

Answer:

$128~ATP$

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

$Number~of~Rounds=\frac{n}{2}-1$

Where "n" is the <u>number of carbons</u>, in this case "18", so:

$Number~of~Rounds=\frac{18}{2}-1~=~8$

We also have to calculate the amount of Acetyl-Coa produced:

$Number~of~Acetyl-Coa=\frac{18}{2}~=~9$

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1 $FADH_2$ and 1 $NADH$ </u>. So, if we have 8 rounds we will have 8 $FADH_2$ and 8 $NADH$ .