Answer:
Explanation:
In this case, we have to start with the <u>reagents</u>:
The compounds given by the problem are:
-) <u>Nitrogen gas</u> = 
-) <u>Water vapor</u> = 
-) <u>Aluminum oxide</u> = 
Now, we can put the products in the <u>reaction</u>:
When we <u>balance</u> the reaction we will obtain:
Now, for the enthalpy change, we have to find the <u>standard enthalpy values</u>:
With this in mind, if we <u>multiply</u> the number of moles (in the balanced reaction) by the standard enthalpy value, we can calculate the energy of the <u>reagents</u>:
And the <u>products</u>:
Finally, for the total enthalpy we have to <u>subtract</u> products by reagents :
I hope it helps!
Answer:
<h2>50 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>50 g/mL</h3>
Hope this helps you
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Each orbital must contain a single electron before any orbital contains two electrons.
4NH3 + 5O2 ==> 4NO + 6H2O Balanced equation
ALWAYS WORK IN MOLES, NOT IN GRAMS
moles of NO produced = 70.5 g NO x 1 mole/30 g = 2.35 moles NO
Since this represents only a 29.8% yield, find what 100% yield would be:
2.35 moles/0.298 = 7.89 moles of NO
From the balanced equation 4 moles NH3 produces 4 moles of NO. Calculate moles of NH3 needed:
7.89 moles NO x 4 moles NH3/4 moles NO = 7.89 moles NH3 needed
Find grams of NH3 needed:
7.89 moles NH3 x 17 g/mole = 134 g NH3 needed
