Answer:
MCO3 is BaCO3
The mass of CO2 produced is 0.28g of CO2
Explanation:
The first step in solving the question is to put down the balanced reaction equations as shown in the image attached. Secondly, we obtain the relative number of moles acid and base as mentioned in the question. The balanced neutralization reaction equation is used to obtain the number of moles of excess acid involved in the neutralization reaction.
This is then subtracted from the total number of moles acid to give the number of moles of acid that reacted with MCO3. From here, the molar mass of MCO3 and identity of M can be found. Hence the mass of CO2 produced is calculated as shown.
The balanced equation for the above double displacement reaction is as follows;
2KCl + Pb(NO₃)₂ ---> PbCl₂ + 2KNO₃
Stoichiometry of KCl to PbCl₂ is 2:1
This means that 2 mol of KCl would react with every 1 mol of PbCl₂
The molarity of KCl - 0.596 M
in 1 L of KCl there are 0.596 mol
Therefore in 10.0 mL of KCl there are -
Number of KCl moles reacted - 0.00596 mol
according to stoichiometry
number of PbCl₂ moles formed - 1/2 x number of KCl moles reacted
Therefore number of PbCl₂ moles formed - 0.00596 mol/2 = 0.00298 mol
molar mass of PbCl₂ - 278 g/mol
mass of PbCl₂ formed - 278 g/mol x 0.00298 mol = 0.828 g
Answer:
The correct answer is True.
Explanation:
In the kidney, the handle of Henle is a fork-like tube located in the nephrons. It is the portion of the nephron that leads from the proximal contoured tubule to the distal contoured tubule. The primary filtrate from the glomerulus passes into the proximal contoured tubule, which connects to the descending branch of the loop of Henle, which has low permeability to ions and urea (solutes) but is very permeable to water.
Have a nice day!