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2 years ago

8

A magnesium oxide component must not fail when a tensile stress of 14 MPa is applied. Determine the maximum allowable surface cr

ack length if the surface energy of magnesium oxide is 1.0 J/m2. The modulus of elasticity of this material is 225 GPa.

1 answer:

ch4aika [34]2 years ago

3 0

Answer:

$x=0.730*10^{-3}m$

Explanation:

From the question we are told that:

Tensile stress $\sigma_c = 14 MPa=>14*10^6$

Modulus of elasticity $E=225GPa=>225*10^9$

Surface energy of MgO $\gamma=1N/m$

Generally the equation for maximum allowable surface crack length is mathematically given by

$x=\frac{2E \gamma}{\pi\sigma_c^2}$

$x=\frac{2(225*10^9)(1)}{3.142*(14*10^6)^2}$

$x=0.730*10^{-3}m$

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In order to fill a tank of 1000 liter volume to a pressure of 10 atm at 298K, an 11.5Kg of the gas is required. How many moles o

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1. A thin plate of a ceramic material with E = 225 GPa is loaded in tension, developing a stress of 450 MPa. Is the specimen lik

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Answer:

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