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Travka [436]
3 years ago
8

A magnesium oxide component must not fail when a tensile stress of 14 MPa is applied. Determine the maximum allowable surface cr

ack length if the surface energy of magnesium oxide is 1.0 J/m2. The modulus of elasticity of this material is 225 GPa.
Engineering
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

x=0.730*10^{-3}m

Explanation:

From the question we are told that:

Tensile stress \sigma_c = 14 MPa=>14*10^6

Modulus of elasticity E=225GPa=>225*10^9

Surface energy of MgO \gamma=1N/m

Generally the equation for maximum allowable surface crack length  is mathematically given by

x=\frac{2E \gamma}{\pi\sigma_c^2}

x=\frac{2(225*10^9)(1)}{3.142*(14*10^6)^2}

x=0.730*10^{-3}m

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