What type of social engineering targets particular?.

assume a strain gage is bonded to the cylinder wall surface in the direction of the axial strain. The strain gage has nominal re

Anastasy [175]

Explanation:

Note: For equations refer the attached document!

The net upward pressure force per unit height p*D must be balanced by the downward tensile force per unit height 2T, a force that can also be expressed as a stress, σhoop, times area 2t. Equating and solving for σh gives:

Eq 1

Similarly, the axial stress σaxial can be calculated by dividing the total force on the end of the can, pA=pπ(D/2)2 by the cross sectional area of the wall, πDt, giving:

Eq 2

For a flat sheet in biaxial tension, the strain in a given direction such as the ‘hoop’ tangential direction is given by the following constitutive relation - with Young’s modulus E and Poisson’s ratio ν:

Eq 3

Finally, solving for unknown pressure as a function of hoop strain:

Eq 4

Resistance of a conductor of length L, cross-sectional area A, and resistivity ρ is

Eq 5

Consequently, a small differential change in ΔR/R can be expressed as

Eq 6

Where ΔL/L is longitudinal strain ε, and ΔA/A is –2νε where ν is the Poisson’s ratio of the resistive material. Substitution and factoring out ε from the right hand side leaves

Eq 7

Where Δρ/ρε can be considered nearly constant, and thus the parenthetical term effectively becomes a single constant, the gage factor, GF

Eq 8

For Wheat stone bridge:

Eq 9

Given that R1=R3=R4=Ro, and R2 (the strain gage) = Ro + ΔR, substituting into equation above:

Eq9

Substituting e with respective stress-strain relation

Eq 10

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7 0

3 years ago

You are approaching an intersection on a multiple-lane road, and you want to change lanes;

Ipatiy [6.2K]

Answer:

The correct answer is B

Explanation:

On a multiple lane roadway that has a speed limit of 50 mph (that is 80.5kmh) or greater, a driver is legally required to signal his or her intention to change lanes at least 300 feet in advance of making the change.

This rule like other traffic rules is design to ensure the safety of other road users by preventing accidents which may stem from reckless driving.

Cheers!

7 0

3 years ago

Read 2 more answers

During the reaction, 3.50 μmol of HCl are produced. Calculate the final pH of the reaction solution. Assume that the HCl is comp

lyudmila [28]

Answer:

The pH of the solution will be equal to 5.46

Explanation:

The dissociation reaction of HCl is equal to:

HCl → H+ + Cl-

To solve the exercise we must first convert the µmoles to moles using the following conversion factor:

3.5µmoles x $\frac{1 mol}{1x10^{6} umol}$ = 3.5x $10^{-6}$ moles

Assuming a liter of solution, we can calculate the molar concentration by:

M = $\frac{Number of moles}{Liter of solution}$

Replacing:

M = $\frac{3.5x10^{-6}moles }{1 L}$ = 3.5x $10^{-6}$ moles/L

As this acid dissociates completely, the concentration of protons and chloride will be equal to 3.5x $10^{-6}$ moles/L

The pH will be equal to:

pH = -log[H+]

Replacing:

pH = -log[3.5x $10^{-6}$ ] = 5.46

8 0

4 years ago

What is the magnitude of the maximum stress that exist at the tip of an internal crack having a radius of curvature of 1.9 x 10-

Hitman42 [59]

Answer:

2800 [MPa]

Explanation:

In fracture mechanics, whenever a crack has the shape of a hole, and the stress is perpendicular to the orientation of such, we can use a simple formula to calculate the maximum stress at the crack tip

$\sigma_{m} = 2 \sigma_{p} (\frac{l_{c}}{r_{c}})^{0.5}$

Where $\sigma_{m}$ is the magnitude of he maximum stress at the tip of the crack, $\sigma_{p}$ is the magnitude of the tensile stress, $l_{c}$ is $1/2$ the length of the internal crack, and $r_{c}$ is the radius of curvature of the crack.

We have:

$r_{c}=1.9*10^{-4} [mm]$

$l_{c}=3.8*10^{-2} [mm]$

$\sigma_{c}=140 [MPa]$

We replace:

$\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}$

We get:

$\sigma_{m} = 2*(140 [MPa])*(\frac{\frac{3.8*10^{-2} [mm]}{2}}{1.9*10^{-4} [mm]})^{0.5}=2800 [MPa]$

5 0

3 years ago

the increase of current when 15 V is applied to 10000ohm rheostat which is adjusted to 1000ohm value

Anastasy [175]

Given data:
•) applied voltage = 15 V
•). Resistance = 1000 ohm

Required:
•). The magnitude of current= ?

•••••••••••••SOLUTION•••••••••••••

We can find the relation ship between current, voltage and resistance with the help of Ohms law.

According to ohms law;

V= IR.

Rearranging the above equation;

I= V/ R

Putt the values in the above equation; we get

I= 15V/ 1000ohm

I = 0.015 A( ampere)

••••••••••••••• CONCLUSION•••••••

The value of the current would be 0.15 ampere when Resistance is equal to 1000 and that of Voltage is equal to 15 V.

4 0

3 years ago