Answer: the half-angle "alpha" of the Mach cone = 30⁰
Explanation:
To calculate the half-angle "alpha" of the Mach cone.
we say ;
Sin∝ = 1 / Ma
given that Ma = 2
now we substitute
Sin∝ = 1 / 2
Sin∝ = 0.5
∝ = Sin⁻¹ 0.5
∝ = 30⁰
Therefore, the half-angle "alpha" of the Mach cone is 30⁰
Answer:
375 KPa
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 125 KPa
Initial temperature (T₁) = 300 K
Final temperature (T₂) = 900 K
Final pressure (P₂) =?
The new (i.e final) pressure of the gas can be obtained as follow:
P₁/T₁ = P₂/T₂
125 / 300 = P₂ / 900
Cross multiply
300 × P₂ = 125 × 900
300 × P₂ = 112500
Divide both side by 300
P₂ = 112500 / 300
P₂ = 375 KPa
Thus, the new pressure of the gas is 375 KPa
Answer:
Explanation:
The stress experimented by the circular bar is:
![\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cleft%5B%5Cfrac%7B2000%5C%2C%20lbf%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%280.5%5C%2Cin%29%5E%7B2%7D%7D%5Cright%5D%5Ccdot%20%5Cleft%28%5Cfrac%7B1%5C%2Ckpsi%7D%7B1000%5C%2Cpsi%7D%20%5Cright%29)
The safety factor is:
