Given:
frequency, f = 60.0 Hz
frequency, f' = 45.0 Hz
Solution:
To calculate max current in inductor, 
:
At f = 60.0 Hz
L = 0.1326 H
Now, reactance 
at f' = 45.0 Hz:
Now, is given by:
Therefore, max current in the inductor, = 2.13 A
Answer:
The amount of energy transferred to the water is 4.214 J
Explanation:
The given parameters are;
The mass of the object that drops = 5 kg
The height from which it drops = 86 mm (0.086 m)
The potential energy P.E. is given by the following formula
P.E = m·g·h
Where;
m = The mass of the object = 5 kg
g = The acceleration de to gravity = 9.8 m/s²
h = The height from which the object is dropped = 0.086 m
Therefore;
P.E. = 5 kg × 9.8 m/s² × 0.086 m = 4.214 J
Given that the potential energy is converted into heat energy, that raises the 1 g of water by 1°C, we have;
The amount of energy transferred to the water = The potential energy, P.E. = 4.214 J.
Answer:
Explanation:
B. you would grab the plug closest to the outlet
