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-BARSIC- [3]
3 years ago
7

Classifying Characteristics of Rocks

Chemistry
1 answer:
aleksklad [387]3 years ago
8 0

Answer:

The texture of a rock is a result of its mineral composition

Most rocks contain more than one type of sediment

Explanation:

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Calculate the volume in liters of a M magnesium fluoride solution that contains of magnesium fluoride . Round your answer to sig
AveGali [126]

The given question is incomplete. the complete question is:

Calculate the volume in liters of a 0.91 M magnesium fluoride solution that contains 249.2 g of magnesium fluoride . Round your answer to 2 significant digits.

Answer: 4.4 Liters

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n}{V_s}

where,

n = moles of solute

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{249.2g}{62.3g/mol}=4.00moles

V_s =volume of solution in L

0.91=\frac{4.00}{V_s}

Thus the volume in liters is 4.4 L

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3 years ago
The top of the saturated zone of soil or rocks is called the
Alika [10]

Answer:

Explanation:

The water table or phreatic surface

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4 years ago
Help please fast as possible I’ll mark you brainlist
Sergeeva-Olga [200]

Answer:

As mass increases the gravitational force increases

Explanation:

Things with mass gain a gravitational force, The bigger they are the more force, for example: the sun is the biggest so it pull us

7 0
3 years ago
How many moles are in 579 grams of Pt
aleksandr82 [10.1K]
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4 years ago
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If 420 joules of heat energy is added to 25 grams of water at 25 degrees celcius, what will be the final temperature of the wate
natka813 [3]

Answer:

T2 = 29°C

Explanation:

Given data:

Heat added = 420 j

Mass of water = 25 g

Initial temperature = 25°C

Final temperature = ?

Solution;

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water = 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values.

420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)

420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)

420 j = 104.5  j/°C × (T2 - 25°C)

420 j /104.5  j/°C = T2 - 25°C

4°C + 25°C = T2

T2 = 29°C

4 0
4 years ago
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