Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).
<h3>How many bowls of cereal would kathy have?</h3>
We know that for each bowl, she needs 1/2 cups of milk.
And we also know that she has a total of (3 + 3/5) cups of milk.
To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:
(3 + 3/5)/(1/2)
We can rewrite the total as:
3 + 3/5 = 15/5 + 3/5 = 18/5
Then the quotient becomes:
(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5
So she can make 7 bowls of cereal (and some leftover milk).
If you want to learn more about quotients:
brainly.com/question/629998
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Answer:
(a) It is an experiment.
(b) Group III has been tested to compare the effect of tea
Step-by-step explanation:
24 volunteers are randomly selected to one of the three groups.
Group I drinks two cups of hot black tea without milk
Group II drinks two cups of hot black tea with milk
Group III drinks two cups of hot water but no tea.
At the end of the month, the researchers measured the change in each of the participant's heart health.
The average change of health status of three Groups can be measured and let it be X1', X2' and X3'. We can set up the hypothesis of no difference of heart health i.e H0 : µ1 = µ2 = µ3 against the alternative hypothesis that they are not equal. As the sample size is less than 30, we can use t-statistic.
Under the above logic, (a) it is an experiment.
(b) Group III has been tested to compare the effect of tea or to have comparison between GroupI and Group III.
Answer:
answer is 12
Step-by-step explanation:
if you take 15 and subtract it by 7 that would give you the number of neon tetra fish, then you can add 4 to give you your total number which is 12 :)
Identify the steps that complete the proof.
♣ = <span>✔ vertical angles theorem</span>
♦ = <span>✔ SAS</span>
♠ = <span><span>✔ CPCTC</span></span>
Answer:
(-2,0)
Step-by-step explanation:
y < |x - 2|
Substitute the points in and check
(-2,0)
0 < |-2 - 2|
0 < |-4|
0 < 4 True
(2,1)
1 < |2 - 2|
1 < |0|
1 < 0 False
(2,0)
0 < |2 - 2|
0 < |0|
0 < 0 False
