The length of rod in terms v(r) and t is L = [ Δt / (1/343) - (1/v(r)) ].
3.56 km/s is the speed of a one-dimensional compressional wave moving along a thin copper rod.
At one end of the rod, a hard hammer strike is delivered. With a time interval of Δt between the two pulses, a listener at the other end of the rod hears the sound twice as it travels through the metal and the air.
The time interval is given by t = L/v.
The delay between pulses arrivals is:
Δt = L [(1/v(air)) - (1/v(copper))]
Now,
When the copper rod is swapped out for a different substance and the sound speed is measured as v(r).
The speed of air, v(air) = 343 m/s
Then,
L = [ Δt / (1/v(air)) - (1/v(r)) ]
L = [ Δt / (1/343) - (1/v(r)) ]
Here L is the length of the rod, Δt is in seconds and v(r) is the speed of sound in the rod.
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An object in motion will remain in motion unless an outside force stops is.
The force of friction is given by:
f = μR, where μ is the friction coefficient and R is the reaction force, which will be equal to the weight.
100 = μ x 130
μ = 0.77
Answer:
V = 20.5 m/s
Explanation:
Given,
The mass of the cart, m = 6 Kg
The initial speed of the cart, u = 4 m/s
The acceleration of the cart, a = 0.5 m/s²
The time interval of the cart, t = 30 s
The final velocity of the cart is given by the first equation of motion
v = u + at
= 4 + (0.5 x 30)
= 19 m/s
Hence the final velocity of cart at 30 seconds is, v = 19 m/s
The speed of the cart at the end of 3 seconds
V = 19 + (0.5 x 3)
= 20.5 m/s
Hence, the final velocity of the cart at the end of this 3.0 second interval is, V = 20.5 m/s
Answer:
D) Grounding
Explanation:
The potential difference between cloud and ground leads to ionization of the atmosphere and resulting conduction through the air often to ground (although it can be between clouds at different potentials. I would say grounding, like the spark when you touch a hot battery terminal to ground on a car.