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Sladkaya [172]
3 years ago
5

Five race cars speed toward the finish line at the Jasper County Speedway. The table lists each car’s speed in meters/second. If

each car has the same mass, which car will require the longest time to come to a full stop?
Car A Car B Car C Car D Car E
890 m/s 850 m/s 790 m/s 895 m/s 870 m/s
Physics
2 answers:
Anarel [89]3 years ago
7 0
I think the answer would be Car C.
igor_vitrenko [27]3 years ago
6 0

Answer:

CAR D

Explanation:

As we know that all cars have same mass so the deceleration of the car that will reduce its speed to rest is given as

a = \frac{F}{m}

so it will be same for all cars.

Now we know by kinematics as

v_f - v_i = at

so time taken by it to stop is given as

t = \frac{v_f - v_i}{a}

here since final speed of all cars is zero so we can say that more initial speed of car will take more time to stop the car.

So longest time will take by Car D

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Kaylis [27]

I assume the 100 N force is a pulling force directed up the incline.

The net forces on the block acting parallel and perpendicular to the incline are

∑ F[para] = 100 N - F[friction] = 0

∑ F[perp] = F[normal] - mg cos(30°) = 0

The friction in this case is the maximum static friction - the block is held at rest by static friction, and a minimum 100 N force is required to get the block to start sliding up the incline.

Then

F[friction] = 100 N

F[normal] = mg cos(30°) = (10 kg) (9.8 m/s²) cos(30°) ≈ 84.9 N

If µ is the coefficient of static friction, then

F[friction] = µ F[normal]

⇒   µ = (100 N) / (84.9 N) ≈ 1.2

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JulsSmile [24]

Answer:

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3 years ago
the brakes on a car do 240000j of work in stopping the car. if the car travels a distance of 40m while the brakes re being appli
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