To solve this problem it is necessary to apply the kinematic equations of angular motion.
Torque from the rotational movement is defined as

where
I = Moment of inertia
For a disk
Angular acceleration
The angular acceleration at the same time can be defined as function of angular velocity and angular displacement (Without considering time) through the expression:

Where
Final and Initial Angular velocity
Angular acceleration
Angular displacement
Our values are given as






Using the expression of angular acceleration we can find the to then find the torque, that is,




With the expression of the acceleration found it is now necessary to replace it on the torque equation and the respective moment of inertia for the disk, so




Therefore the torque exerted on it is 
Answer:
because its not going down a long hill instead its going on a leveled street
We will use this equation:
s = 1/2*a*t^2 + v0*t + s0
where:
s = space traveled
a = acceleration
t = time
v0 = initial speed
s0 = initial space
In this case::
v0 = 0
s0 = 0
So our equation will look like that now:
s = 1/2 * a * t^2
let's calculate the acceleration first of all:
a = (vf - vi) / t
where vf is the final speed and vi is the initial speed. t is the time.
a = (25m/s) / 10s = 2.5 m/s^2
Now we can calculate the space:
s = 1/2 * (2.5 m/s^2) * (10s)^2 = 125m
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Hope it was helpful! Have a great day.
Milky Way Galaxy, same one as you.
Answer:
Average density of Sun is 1.3927
.
Given:
Radius of Sun = 7.001 ×
km = 7.001 ×
cm
Mass of Sun = 2 ×
kg = 2 ×
g
To find:
Average density of Sun = ?
Formula used:
Density of Sun = 
Solution:
Density of Sun is given by,
Density of Sun = 
Volume of Sun = 
Volume of Sun = ![\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%203.14%20%5Ctimes%20%5B7.001%20%5Ctimes%2010%5E%7B10%7D%5D%5E%7B3%7D)
Volume of Sun = 1.436 ×

Density of Sun = 
Density of Sun = 1.3927 
Thus, Average density of Sun is 1.3927
.