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Gnoma [55]
3 years ago
7

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Step-by-step explanation:

5x + 27 \geqslant 6x + 26 \\ 5x - 6x \geqslant 26 - 27 \\  - x \geqslant  - 1 \\ then \: change \: the \: sign \: into \: less \: than \: or \: equal \\  \frac{ - x}{ - 1}  =  \frac{ - 1}{ - 1}   \\ x = 1

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At a local​ museum, a statue must be at least 187 centimeters tall for display purposes. Rita wants to give the museum the statu
Inessa05 [86]

Answer:

yes

Step-by-step explanation:

C.

3 0
1 year ago
Read 2 more answers
A RIGHT triangle has two other angles measuring x and 2x. What does x equal?
Marianna [84]

Answer:

x = 30

Step-by-step explanation:

because the interior angles of a triangle = 180° so if you subtract 90° you get 90. in order to get 90 you can use the equation x + 2x = 90 which you will then get x = 30

5 0
3 years ago
Part A: Find a rational number that is between 7.7 and 7.9. Explain why it is rational. (2 points)
cluponka [151]
Part A.
7.8 is a rational number between 7.7 and 7.9.
It is rational because it can be written as a fraction of integers, such as 78/10.

Part B.
sqrt(60) = 7.75
sqrt(60) cannot be written as a fraction of integers. It is a decimal number that never ends and never repeats.
7 0
3 years ago
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

8 0
3 years ago
What is the value of -5(m - 2) when m = -1
Lana71 [14]
-5(-1-2)
5+10
15

Or

-5(-1-2)
-5(-3)
15

It's 15 either way.
7 0
3 years ago
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