Grams of Chromium(III) nitrate produced : 268.95 g
<h3>Further explanation</h3>
Given
0.85 moles of Lead(IV) nitrate
Required
grams of Chromium(III) nitrate
Solution
Reaction
Balanced equation :
<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>
From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃
mol Cr(NO₃)₃ =
Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :
mass = mol x MW
mass = 1.13 x 238.0108
mass = 268.95 g
The increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.
<h3>What is equilibrium?</h3>
The equilibrium of the gas is based on the pressure of the gas. With the increase in pressure, the equilibrium moves towards making fewer molecules of gas.
The gas equilibrium is proportional to the equilibrium K.
Increase in volume shift the equilibrium towards making more moles of gas, decrease in volume shift the equilibrium towards producing fewer moles of gas.
Learn more about equilibrium
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Answer:
moles, liter, concentration, and 6.0 mol/L
Explanation:
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