Answer:
Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺
Explanation:
Data Given:
Reactants:
Ni(s) + H₂O(l)
Product = ?
Solution:
Names of the Reactants
Ni = Nickel
H₂O = water
Reaction:
Normally nickel directly does not react with water under normal condition. But indirectly in acidic or neutral condition it form complex ion.
For this it first dissolve slowly in dilute acid, in this reaction it liberate Ni²⁺ ions these nickel ions form light green complex ions in aqueous solution.
Ni(s) + H₂SO₄(aq) -------> Ni²⁺(aq) + SO₄²⁻(aq) + H₂
This is a type of complex formation in which Nickel react with water and produced a light green color new complex ion or product.
Complete reaction is as under
Ni(s) + H₂O(l) -------------> [Ni(H₂O)₆]²⁺
Balance Reaction:
Ni(s) + 6 H₂O(l) -------------> [Ni(H₂O)₆]²⁺
So.
by this reaction one product is formed that is [Ni(H₂O)₆]²⁺ named as hexaqua nickel ion
Answer:
i think the answer is letter C. From 35°c to 45°c
Explanation:
sorry if it is wrong
<span>All of them are highly reactive nonmetals.</span>
<h3>Answer:</h3>
3.2 moles of Oxygen
<h3>Explanation:</h3>
Acetic Acid having chemical formula C₂H₄O₂ and structural formula attached below is the second member of carboxylic family in organic compounds. It is commonly used as vinegar<em> i.e</em>. a mixture containing 5 % Acetic acid and 95 % water.
As shown in structure 1 mole of Acetic acid contains 2 moles of Carbon atoms, 4 moles of Hydrogen atoms and 2 moles of Oxygen atoms respectively. Hence, the number of moles of Oxygen atoms contained by acetic acid containing 3.2 moles of Carbon is calculated as,
2 moles of C accompany = 2 moles of O
So,
3.2 moles of C will accompany = X moles of O
Solving for X,
X = (3.2 mol C × 2 mol O) ÷ 2 mol C
X = 3.2 mol of Oxygen
