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yaroslaw [1]
3 years ago
9

What is the equation of a circle with a radius of 6 and a center at ( -2 , 3 )?

Mathematics
2 answers:
Gnom [1K]3 years ago
6 0

Answer:

Solution given:

centre(h,k)=(-2,3)

radius(r)=6 units

we have

equation of a circle is:

(x-h)²+(y-k)²=r²

(x+2)²+(y-3)²=6²

<u>(x+2)²+(y-3)²=36</u> is <u>required</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>o</u><u>f</u><u> </u><u>a</u><u> </u><u>c</u><u>i</u><u>r</u><u>c</u><u>l</u><u>e</u><u>.</u>

jekas [21]3 years ago
3 0
The formula for a circle is:

(x-p)^2+(y-q)^2=r^2

The radius is given (r=6), as well as the centre of the circle (-2;3).

"p" and "q" represent the coordinates of the centre of the circle.

So it would look like this -

(x-p)^2+(y-q)^2=r^2

p=x-coordinate (-2)
q=y-coordinate (3)
r=6

(x-(-2))^2+(y-(3))^2 =6^2
(x+2)^2 + (y-3)^2 = 36

***"^" means "to the power of"

Hope this helped~
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The inverse of the given function is y = √5x + 7/2 - 3

<h3>Inverse of a function</h3>

Given the function expressed below;

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learn more on inverse of a function here: brainly.com/question/3831584

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