Question

What is the equation of a circle with a radius of 6 and a center at ( -2 , 3 )?

Answer 1

Answer:

Solution given:

centre(h,k)=(-2,3)

radius(r)=6 units

we have

equation of a circle is:

(x-h)²+(y-k)²=r²

(x+2)²+(y-3)²=6²

(x+2)²+(y-3)²=36 is required equation of a circle.

Answer 2

The formula for a circle is:

(x-p)^2+(y-q)^2=r^2

The radius is given (r=6), as well as the centre of the circle (-2;3).

"p" and "q" represent the coordinates of the centre of the circle.

So it would look like this -

(x-p)^2+(y-q)^2=r^2

p=x-coordinate (-2)
q=y-coordinate (3)
r=6

(x-(-2))^2+(y-(3))^2 =6^2
(x+2)^2 + (y-3)^2 = 36

***"^" means "to the power of"

Hope this helped~