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4 years ago

Magma is formed by

1 answer:

7 0

magma is the lava before it comes out of the earth so the answer is rocks being pushed into the mantle and melting hope I was helpful

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Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

harkovskaia [24]

Answer:

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

Explanation:

Wavelength of the light = $\lambda = 430 nm=4.30\times 10^{-7} m$

Speed of the light = c = $= 3\times 10^8 m/s$

Frequency of the light = $\nu$

$\nu =\frac{c}{\lambda }$

$\nu =\frac{3\times 10^8 m/s}{4.30\times 10^{-7} m}=6.98\times 10^{14} s^{-1}$

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

5 0

4 years ago

Why are atoms always bonded

postnew [5]

Atoms are always bonded so that nearby atoms have to form into a compound and can be classified into different forms of compounds or molecules. It is also integral in our everyday life.

6 0

3 years ago

Which element in group 1 has the greatest tendency to lose an electron?

77julia77 [94]

A. cesium. bacause as the elements go down a group of the atoms, the sizes of the atom will increase . we know that tge tendency to lose an electron is based on the sizes of the atoms of group 1.

7 0

3 years ago

Read 2 more answers

Which phrase best describes bronze?

11111nata11111 [884]

Answer:

o A copper-tin alloy

Explanation:

Bronze is composed by copper and tin. This means it is not a pure metal.

Bronze cannot be mined, so it is not a mineral ore.

An ionic compound of copper and tin could also be theoretically used to describe a non-solid ionic compound of copper and tin. However bronze is solid.

Hence the answer is A copper-tin alloy.

7 0

3 years ago

If 50 ml of 0.235 M NaCl solution is diluted to 200.0 ml what is the concentration of the diluted solution

Helen [10]

This is a straightforward dilution calculation that can be done using the equation

$M_1V_1=M_2V_2$

where M₁ and M₂ are the initial and final (or undiluted and diluted) molar concentrations of the solution, respectively, and V₁ and V₂ are the initial and final (or undiluted and diluted) volumes of the solution, respectively.

Here, we have the initial concentration (M₁) and the initial (V₁) and final (V₂) volumes, and we want to find the final concentration (M₂), or the concentration of the solution after dilution. So, we can rearrange our equation to solve for M₂:

$M_2=\frac{M_1V_1}{V_2}.$

Substituting in our values, we get

$\[M_2=\frac{\left ( 50 \text{ mL} \right )\left ( 0.235 \text{ M} \right )}{\left ( 200.0 \text{ mL} \right )}= 0.05875 \text{ M}\].$

So the concentration of the diluted solution is 0.05875 M. You can round that value if necessary according to the appropriate number of sig figs. Note that we don't have to convert our volumes from mL to L since their conversion factors would cancel out anyway; what's important is the ratio of the volumes, which would be the same whether they're presented in milliliters or liters.

5 0

3 years ago