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Dima020 [189]
3 years ago
5

PART A: Which of the following identifies the central idea of the text? The text is the power of advertising

Chemistry
2 answers:
Afina-wow [57]3 years ago
7 0

Answer: B

Explanation:

Semenov [28]3 years ago
4 0

Answer: B- Advertising are capable of manipulating...

Explanation:

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Which of these solutes raises the boiling point of water the most?
Vlad [161]
I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
7 0
3 years ago
Read 2 more answers
a scientists finds an organism that cannot move. it has many cells, produces spores, and gets food from its environment. in whic
lord [1]

The correct answer is : The Organism belongs in Kingdom Fungi


The explanation:


1) because Fungi can be multicellular


2) most of them cannot move.


3) They can get food by releasing digestive juices into their environment.

3 0
3 years ago
A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )
Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

Explanation:

Number of moles of HCl present initially = \frac{0.1200}{1000}\times 50.0 moles = 0.00600 moles

Neutralization reaction (back titration): NaOH+HCl\rightarrow NaCl+H_{2}O

According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

3 0
3 years ago
No I don’t have a question
Nikitich [7]

Answer:

then why'd you ask a question

Explanation:

3 0
2 years ago
12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?
bazaltina [42]

Answer:

u=4.57x10^5GHz

Explanation:

Hello.

In this case, given the formula:

E=h*u

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\  \\u=4.57x10^{14}s^{-1}

Or also:

u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz

Best regards.

5 0
3 years ago
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