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3 years ago

Which of these measures a wavelength.

Physics

1 answer:

ch4aika [34]3 years ago

8 0

Answer:

Explanation:

To measure wavelength, you would find the distance from crest (top of the wave) to crest.

Hope this helps! :)

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PLEASE HELP ME, ILL GIVE BRAINLIEST<br><br> Which image is a correctly labeled prokaryotic cell?

yulyashka [42]

Answer:

I believe it's the bottom left :)

Explanation:

4 0

3 years ago

Read 2 more answers

Commercially-available hybrid vehicles, such as the Toyota Prius, use electrical batteries to store energy for later use. Howeve

Bad White [126]

(A) $4.2\cdot 10^5 J$

The energy stored by the system is given by

$E=Pt$

where

P is the power provided

t is the time elapsed

In this case, we have

P = 60 kW = 60,000 W is the power

t = 7 is the time

Therefore, the energy stored by the system is

$E=(60,000 W)(7 s)=4.2\cdot 10^5 J$

(B) 4830 rad/s

The rotational energy of the wheel is given by

$E=\frac{1}{2}I \omega^2$ (1)

where

$I$ is the moment of inertia

$\omega$ is the angular velocity

The moment of inertia of the wheel is

$I=\frac{1}{2}MR^2=\frac{1}{2}(5 kg)(0.12 m)^2=0.036 kg m^2$

where M is the mass and R the radius of the wheel.

We also know that the energy provided is

$E=4.2\cdot 10^5 J$

So we can rearrange eq.(1) to find the angular velocity:

$\omega=\sqrt{\frac{2E}{I}}=\sqrt{\frac{2(4.2\cdot 10^5 J)}{0.036 kg m^2}}=4830 rad/s$

(C) $2.8\cdot 10^6 m/s^2$

The centripetal acceleration of a point on the edge is given by

$a=\omega^2 R$

where

$\omega=4830 rad/s$ is the angular velocity

R = 0.12 m is the radius of the wheel

Substituting, we find

$a=(4830 rad/s)^2 (0.12 m)=2.8\cdot 10^6 m/s^2$

7 0

4 years ago

The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these

harina [27]

Answer:

Electric field magnitude

E = K/qd

Where

K = kinetic energy of electron

d = electron distance

q = charge

Explanation:

Given the relationship between workdone and energy

Work-energy theorem:

Net workdone = Energy change

W = ∆E

In this case

W = ∆K.E

And,

∆K.E = K(final) - K(initial)

To stop the kinetic energy | K(final) = 0

K(initial) = K (given)

∆K.E = 0 - K = -K

Let the electric force on the electron has magnitude F.

And

W = -Fd = ∆K.E = -K

-Fd = -K

F = K/d .....1

The magnitude of the electric field E that can stop these electron in a distance d:

E = F/q ......2

Where q is the charge on electron.

substituting equation 1 to 2

E = (K/d)/q = K/qd

E = K/qd

3 0

4 years ago

If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed? (e = 1.60 × 10-19

Nata [24]

Answer:

So speed of electron will be $5.89\times 10^{-7}m/sec$

Explanation:

We have given potential difference V = 9.9 KV

Charge on electron $e=1.6\times 10^{-19}$

So energy of electron $E=eV=1.6\times 10^{-19}\times 9.9\times 10^3=15.84\times 10^{-16}J$

This energy of electron will be equal to kinetic energy of electron

So $\frac{1}{2}mv^2=15.84\times 10^{-16}J$

$\frac{1}{2}\times 9.11\times 10^{-31}v^2=15.84\times 10^{-16}$

$v=5.89\times 10^{-7}m/sec$

So speed of electron will be $5.89\times 10^{-7}m/sec$

8 0

3 years ago

In a ____ wave, pasticles of the medium move perpendicular<br> to the direction of the wave.

GrogVix [38]

The answer is transverse

6 0

3 years ago