Answer:
The frequency of the second wave is half of the frequency of first one.
Explanation:
The wavelength of the second wave is double is the first wave.
As we know that the frequency is inversely proportional to the wavelength of the velocity is same.
velocity = frequency x wavelength
So, the ratio of frequency of second wave to the first wave is
The frequency of the second wave is half of the frequency of first one.
Answer:
0.014 kg
Explanation:
trust me its right i took the assessment and got 100%. :)
Answer:
The kinetic energy for both objects is the same.
Explanation:
While in other cases the kinetic energies of two objects that have different masses might be different depending on their velocities, in this case both the 3 kg book and 5 kg bowling ball have the same kinetic energy.
This is because kinetic energy is calculated using the formula: K = 1/2 * m * v^2, where m represents the mass and v represents the velocity of the object.
Since the book and the bowling ball are sitting still on the floor, their velocities are zero. Hence, when we plug in 0 for velocity into the equation for kinetic energy, we will get that the kinetic energy is 0 for the book and the bowling ball.
Hope this helps!
Answer:
q₃ = - 13.0935 μC
Explanation:
Given
q₁ = q₂ = +7.67 μC
We use the equation
V = Kq/r
We can apply it as follows
V₁ = K*q₁/r₁ = K*q₁/(√2*L)
V₂ = K*q₂/r₂ = K*q₂/L
V₃ = K*q₃/r₃ = K*q₃/L
Then
V₁ + V₂ + V₃ = 0
⇒ (K*q₁/(√2*L)) + (K*q₂/L) + (K*q₃/L) = 0
⇒ (K/L)*((q₁/√2) + q₂ + q₃) = 0
⇒ (q₁/√2) + q₂ + q₃ = 0
Since q₁ = q₂
⇒ (q₁)((1/√2) + 1) + q₃ = 0
⇒ q₃ = - (q₁)((1/√2) + 1) = +7.67 μC*(1.7071)
⇒ q₃ = - 13.0935 μC