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Serjik [45]
2 years ago
7

Which metallloid has three valence electrons?

Physics
1 answer:
Naya [18.7K]2 years ago
8 0
Boron Group
elements have three valence electrons and are fairly reactive. All of them are solids at room temperature. Boron is a very hard, black metalloid with a high melting point.
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this is a 3 part questionOn vacation, your 1400-kg car pulls a 560-kg trailer away from a stoplight with an acceleration of 1.85
mamaluj [8]

ANSWER:

(a) 1036 N

(b) -1036 N

(c) 2590 N

STEP-BY-STEP EXPLANATION:

Given:

Mc = 1400 kg

Mt = 560 kg

a = 1.85 m/s^2

(a)

Force by car on trailer:

\begin{gathered} F_c=m\cdot a \\ F_c=560\cdot1.85 \\ F_c=1036\text{ N} \end{gathered}

(b)

\begin{gathered} F_t=-F_c \\ F_t=-1036\text{ N} \end{gathered}

(c)

\begin{gathered} F_n=1400\cdot1.85 \\ F_n=2590\text{ N} \end{gathered}

3 0
11 months ago
. Why are scientific models important? They help scientists prove scientific theories. They help scientists explain complex ques
sdas [7]
The best answer would be the 4th choice. "They help scientists explain concepts that are difficult to observe, this also covers the first answer which helps the scientist to answer complex questions. A scientific model is not used prove scientific laws as they may not always have all the data to prove so, instead it is used to allow them to explain better concepts revolving around science through research and may also allow them to predict results based on the accumulation of data and analyzing the trend of this resulting information.
3 0
3 years ago
A 1090 kg car has four 12.7 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to ro
max2010maxim [7]

Answer:

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

Explanation:

To develop this exercise we proceed to use the kinetic energy equations,

In the end we replace

KE_{Total}=KE_{Translational}+KE_{Rotational}

KE_{Total}=\frac{1}{2}m_{car}+4*\frac{1}{2}*I*(\frac{v}{r})^2

Here

I=\frac{1}{2}m_{wheels}*r^2 meaning the 4 wheels,

So replacing

KE_{Rotational}=4\frac{1}{2}*(\frac{1}{2}m_{wheels}*r^2)*(\frac{v}{r})^2=m*v^2

So,

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}*v^2}{\frac{1}{2}m_{car}*v^2+m_{wheels}*v^2}

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}}{\frac{1}{2}m_{car}+m_{wheels}}

\frac{KE_{Rotational}}{KE_{Total}} =  \frac{10}{545+10}

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

3 0
3 years ago
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babymother [125]

Answer:

9.8 secs

Explanation:

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English please !!!!!!!
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