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3 years ago

What is true of an object pulled inward in an electric field?

Physics

1 answer:

slava [35]3 years ago

5 0

Answer:

option b

Explanation:

There is an object pulled inward in an electric field.

We have to find out of the four options given which is true.

a) The object has a neutral charge is false since when electric field pulls the object inward, there is a charge inside.

b) The object has a charge opposite that of the field, this option is correct since there will be an equal and opposite charge created by the object

c) The object has a negative charge will be correct only if the original charge was positive hence wrong

d) The object has a charge the same as that of the field is incorrect since this would be opposite the charge

So only option b is right

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If a vehicle accelerating at 2.7 m/s2what is it's velocity at 20 meters 12.63m/s,1.03m/s,10.39m/s,6.39m/s

netineya [11]

Answer:

The final velocity of the vehicle is 10.39 m/s.

Explanation:

Given;

acceleration of the vehicle, a = 2.7 m/s²

distance moved by the vehicle, d = 20 m

The final velocity of the vehicle is calculated using the following kinematic equation;

v² = u² + 2ah

v² = 0 + 2 x 2.7 x 20

v² = 108

v = √108

v = 10.39 m/s

Therefore, the final velocity of the vehicle is 10.39 m/s.

5 0

3 years ago

Vera and her three sisters received the same amount of money to go to the school festival. Each girl spent $12. Afterward, the g

rodikova [14]

Answer:

$18

Explanation:

Each of the was qiven $18

All together =24

24 divide it by 4 (because there were 4 people there)

= 6 (6+6+6+6)

= 24

=6+12=18

.Hence each of them was given $18

7 0

2 years ago

3 questions 35 points

bearhunter [10]

The answer to question one would be Ethier A or D and the answer to question number 2 is B friction the answer to question number 3 is B kinetic energy

4 0

3 years ago

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A force of 140 140 newtons is required to hold a spring that has been stretched from its natural length of 40 cm to a length of

icang [17]

Answer:

The work done in stretching the spring is 0.875 J.

Explanation:

Given that,

Force = 140 N

Natural length = 60-40 = 20 cm

Stretch length of the spring = 65-60 = 5 cm

We need to calculate the spring constant

Using formula of Hooke's law

$F= kx$

$140=k\times20\times10^{-2}$

$k=\dfrac{140}{20\times10^{-2}}$

$k=700$

We need to calculate the work done

$W=\int_{a}^{b}{kx}dx$

$=\int_{0}^{0.05}{700x}dx$

On integration

$W=700\times(\dfrac{x^2}{2})_{0}^{0.05}$

$W=700\times(\dfrac{(0.05)^2}{2}-0)$

$W=0.875\ J$

Hence, The work done in stretching the spring is 0.875 J.

3 0

3 years ago

Calculate the potential difference between points x and y

aliya0001 [1]

Answer:

4.275v

<u><em>Thank you </em></u>

8 0

3 years ago

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