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vodomira [7]
3 years ago
5

A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,

if the new pressure is 1.97 atm and the new volume is 2.78 L?
Chemistry
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

The answer to your question is:   T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L                    V2 = 2.78 L

P1 = 2.40 atm               P2 = 1.97 atm

T1 = 325°K                    T2 = ?

Formula

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Process

            T2 = (P2V2T1) / (P1V1)

            T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

            T2 = 1779.895 / 7.56

            T2 = 235.44 °K

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Explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

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Number of moles of NO₂ produced :

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now we will compare the moles of NO₂   with N₂O₅.

                NO₂          :       N₂O₅

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4 0
3 years ago
2 Na + Cl2 --&gt; 2 NaCl<br> What is the mole ratio of sodium to sodium chloride?
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6 0
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Answer:

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Personal opinion/interpretation are usually firsthand explanation to a phenomenon or problem set. They are usually drawn from logical reasoning and deduction about some event. Most times, they are non-scientific in nature in that they are non-methodical and do not rely on the critical thinking precepts scientific studies are hinged on.

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5 0
3 years ago
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