<u>Given:</u>
Moles of He = 15
Moles of N2 = 5
Pressure (P) = 1.01 atm
Temperature (T) = 300 K
<u>To determine:</u>
The volume (V) of the balloon
<u>Explanation:</u>
From the ideal gas law:
PV = nRT
where P = pressure of the gas
V = volume
n = number of moles of the gas
T = temperature
R = gas constant = 0.0821 L-atm/mol-K
In this case we have:-
n(total) = 15 + 5 = 20 moles
P = 1.01 atm and T = 300K
V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L
Ans: Volume of the balloon is around 488 L
Answer:
1st = saturated
Explanation:
Bro first ka answer saturated he
Answer:
156.8kPa
Explanation:
The problem here is to convert mmHg to kPa;
We have been given:
1176mmHg and the problem is to convert to kPa;
1000Pa = 1kPa
1 mmHg = 133.322Pa
1176mmHg will give 1176 x 133.322 = 156787.1Pa
To kPa;
156.8kPa
When winds move air masses, they carry their weather conditions (heat or cold, dry or moist) from the source region to a new region. When the air mass reaches a new region, it might clash with another air mass that has a different temperature and humidity. This can create a severe storm.
