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Lerok [7]
3 years ago
6

Acetylene gas, C2H2, releases large quantities of heat when it burns, making it ideal for welding applications. This gas is gene

rated by reacting calcium carbide with excess water. Calcium hydroxide is a byproduct of this reaction. If you needed 26kg of acetylene to fill a cylinder, how many kg calcium carbide would you need to order?
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

64 kg

Explanation:

The computation of the number of kg need to ordered is shown below:

As we know that

CaC_2 + 2H_2O \rightarrow Ca(OH)^2   + C_2H_2

Now as we know that

1  mole of C_2H_2 generated from 1 mole of CaC_2

Now

26g of C_2H_2 generated from 64g of CaC_2

And,

26kg of C_2H_2 generated from

= \frac{64g\times26Kg}{26g}

= 64kg CaC_2

Hence, the number of kg that required for ordering the calcium carbide is 64 kg

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Answer:

The steps are explained below, the essential step is to find mass here, 120 g of NaOH.

Explanation:

In order to answer this question, we need to define molarity conceptually firstly to see what variables we need. According to the formula, molarity is equal to the ratio between moles and volume, while moles itself is a ratio between mass and molar mass. This means we have a formula for molarity involving mass, molar mass and volume:

c = \frac{n}{V} = \frac{m}{MV}

In order to prepare a 500.0 mL of stock solution of 6.0 M of NaOH, we then need to find the mass of NaOH dissolved in this solution using the equation above:

m = cMV = 6.0 M\cdot 39.997 g/mol\cdot 0.5000 L = 120 g

Now, since we have the mass of NaOH, we can describe the steps needed to prepare this solution:

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Our solution is prepared.

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4 years ago
What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
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p = 75 kPa, pressure

Use the ideal gas law, given by
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Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

Answer: 0.363 m³
    
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