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Lerok [7]
3 years ago
6

Acetylene gas, C2H2, releases large quantities of heat when it burns, making it ideal for welding applications. This gas is gene

rated by reacting calcium carbide with excess water. Calcium hydroxide is a byproduct of this reaction. If you needed 26kg of acetylene to fill a cylinder, how many kg calcium carbide would you need to order?
Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
5 0

Answer:

64 kg

Explanation:

The computation of the number of kg need to ordered is shown below:

As we know that

CaC_2 + 2H_2O \rightarrow Ca(OH)^2   + C_2H_2

Now as we know that

1  mole of C_2H_2 generated from 1 mole of CaC_2

Now

26g of C_2H_2 generated from 64g of CaC_2

And,

26kg of C_2H_2 generated from

= \frac{64g\times26Kg}{26g}

= 64kg CaC_2

Hence, the number of kg that required for ordering the calcium carbide is 64 kg

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Determine the empirical formula. a 3.880g sample contains 0.691g of magnesium , 1.84 g of sulfur , and 1.365 g of oxygen .
Aliun [14]

Answer:

Mg S2 O3

Explanation:

.691 g of Mg  is .284 mole

1.84 g of S    is .5739 mole

1.365 g of O is  .8531 mole      you can see the ratio is ~  1 :2 :3

                                                        Mg S2 O3

4 0
2 years ago
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Yakvenalex [24]
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4 0
3 years ago
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CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
padilas [110]

<u>Answer:</u> The \Delta G for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm

Putting values in above equation, we get:

K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85

To calculate the gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol

Hence, the \Delta G for the reaction is 54.425 kJ/mol

7 0
3 years ago
How many chlorine atoms are there in 12.2 g of ccl4? How many chlorine atoms are there in 12.2 of ? 4.77×1022 atoms?
mash [69]

Answer:- 1.91*10^2^3Cl atoms.

Solution:- We have been given the grams of carbon tetrachloride and asked to calculate the number of atoms of chlorine. It is a three step conversion problem. In the first we convert the grams of carbon tetrachloride to moles of it. In second step we convert moles of carbon tetrachloride to moles of chlorine and in the third step we convert the moles of chlorine to atoms of chlorine.

For grams to mole conversion we need the molar mass of the compound. Molar mass of carbon tetrachloride is 153.82 grams per mol. If we look at the formula of carbon tetrachloride then four chlorine are present in it. It means 1 mol of carbon tetrachloride has four moles of chlorine. The calculations are as follows:

12.2gCCl_4(\frac{1molCCl_4}{153.82gCCl_4})(\frac{4molCl}{1molCCl_4})(\frac{6.02*10^2^3Clatoms}{1molCl})

= 1.91*10^2^3Cl atoms

So, there are 1.91*10^2^3Cl atoms in 12.2 grams of CCl_4 .

6 0
3 years ago
Read 2 more answers
How many atoms of each element are in the chemical formula P2O5?
marshall27 [118]

Answer:A

Explanation:2 phosphorus and 2 oxygen

4 0
3 years ago
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