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schepotkina [342]
3 years ago
15

Look at the dots around each symbol and the energy levels from the resources above;

Chemistry
1 answer:
Anton [14]3 years ago
6 0

Hello! Here's the answer I was able to come up with:

<em>Why does Na have only one dot?</em>

Sodium, or Na, has only one valence electron.  (This makes the atom tend to participate in ionic bonding and "give" its single valence electron to an atom like chlorine.)

<em>Why do none of these diagrams show more than 8 dots?</em>

It is physically impossible for an atom to have more than 8 electrons in its valence layer, according to the Octet Rule.

<em>What relationship do you notice between the dots in these two charts?</em>

The dot diagram for each element represents the number of electrons each element will have in its outermost, or valence, shell. (2-8-8)

<em>The number of dots that hydrogen and helium have in their dot diagram is the same as the number of electrons shown for them on the Periodic Table. Why?</em>

An atom can have a maximum of two electrons in its innermost layer. Hydrogen and helium have only one and two electrons, respectively, so they don't have enough electrons to actually have more than one layer. Therefore, their outermost layer is, in fact, their only layer. This is why the number of dots that hydrogen and helium have in their dot diagram is the same as the number of electrons shown for them on the Periodic Table.

Don't copy this word for word! You will most likely be in trouble for plagiarism.  Instead, rewrite these ideas in your own words, or paraphrase. Good luck, and I know you can do it! ♥  

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SOVA2 [1]

Answer:

Option 2

Explanation:

3 0
3 years ago
How can a scientist prevent bias in a scientific investigation
BaLLatris [955]
They must make sure that all things pointed out are fact, not opinion.
5 0
2 years ago
A mixture of carbon dioxide and helium gases is maintained in a 7.91 L flask at a pressure of 1.42 atm and a temperature of 33 °
Crank

Answer:

The gas mixture contains 1.038 grams of helium

Explanation:

<u>Step 1:</u> Data given

Volume of the flask = 7.91 L

Total Pressure = 1.42 atm

Temperature = 33 °C

Mass of CO2 = 8.25 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of He = 4 g/mol

<u>Step 2</u>: Calculate total number moles of gas

p*V = n*R*T

⇒ p = the pressure = 1.42 atm

⇒ V = the volume = 7.91 L

⇒ n= the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L* atm/K*mol

⇒ T = the temperature = 33 °C = 306 Kelvin

n = (p*V)/(R*T)

n = (1.42*7.91)/(0.08206 * 306)

n = 0.447 moles

<u>Step 3</u>: Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 8.25 grams / 44.01 g/mol

Moles CO2 = 0.1875 moles

<u>Step 4:</u> Calculate moles of Helium

Moles Helium = total moles of gas - moles of CO2

Moles Helium = 0.447 - 0.1875 = 0.2595 moles of helium

<u>Step 5: </u> Calculate mass of helium

Mass of helium = moles of helium * molar mass of helium

Mass of helium = 0.2595 moles * 4 g/mol

Mass of helium = 1.038 grams

The gas mixture contains 1.038 grams of helium

8 0
2 years ago
If the starting volume of a hot air balloon is 55,500 m3and the initial temperature is 21 °C, what is the temperature inside the
Dmitry_Shevchenko [17]

Answer:

T₂ = 392 K

Explanation:

Given that,

Initial volume of the hot air balloon, V₁ = 55500 m³

Initial temperature, T₁ = 21°C = 294 K

Final volume, V₂ = 74000 m³

We need to find the final temperature inside the balloon. The relation between the temperature and volume is given by charles law i.e.

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

Where

T₂ is the final temperature

So,

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\T_2=\dfrac{T_1V_2}{V_1}\\\\T_2=\dfrac{294\times 74000 }{55500 }\\\\T_2=392\ K

So, the new temperature is 392 K.

8 0
2 years ago
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons
elena-s [515]

Answer:

-372000 J or -372 KJ

Explanation:

We have the electrochemical reaction as;

Mg(s)  +  Fe^2+(aq)→  Mg^2+(aq)  +   Fe(s)

We must first calculate the E∘cell from;

E∘cathode -  E∘anode

E∘cathode = -0.44 V

E∘anode = -2.37 V

Hence;

E∘cell = -0.44 V -(-2.37 V)

E∘cell = 1.93 V

n= 2 since two electrons were transferred

F=96,500C/(mol e−)

ΔG∘=−nFE∘

ΔG∘= -( 2 * 96,500 * 1.93)

ΔG∘= -372000 J or -372 KJ

4 0
2 years ago
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