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iren2701 [21]
4 years ago
15

What is the maximum length of a polyethene chain with molar mass 10^6 and monomer length 2.5?

Chemistry
1 answer:
ziro4ka [17]4 years ago
7 0

Answer:

L=7.0125*10^-5

Explanation:

LET  

 Length of polyethene chain= L

Molecular weight OF polyethene= MW

Molecular weight of monomer =mw

Monomer length= l

L=(MW/mw) *l

              L= (28.05g/mol10^6gmol-1) * 2.5

             L=70.125*10^-6

            L=7.0125*10^-5

Hence, the length will be L=7.0125*10^-5 .

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Calculate the molar mass of a gas if an 8.06×10(to the power of -2) gram sample of it occupies .0650 L at 547°C and 70.5 kPa​
notsponge [240]

Answer:

                     M.Mass = 120 g/mol

Explanation:

Data Given:

                  Volume = V = 0.0650 L

                  Temperature = T = 547 °C = 820.15 K

                  Pressure = P = 70.5 kPa = 0.695 atm

                  Gas Constant = R = 0.082057 L.atm.mol⁻¹.K⁻¹

Formula Used:

                        Assuming that the gas is ideally then according to ideal gas equation,

                                   P V = n R T

Solving for n,

                                   n = P V / R T

Putting Values,

    n = (0.695 atm × 0.0650 L) ÷ (0.082057 L.atm.mol⁻¹.K⁻¹ × 820.15 K)

    n = 6.71 × 10⁻⁴ moles

Now, Knowing that,

                                  Moles  =  Mass / M.Mass

Or,

                                  M.Mass = Mass / Moles

Putting values,

                                  M.Mass = 8.06 × 10⁻² g / 6.71 × 10⁻⁴ mol

                                  M.Mass = 120 g/mol

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