<span>The question says,'Mathew was working with different concentrations of hydrochloric acid in the lab. Which of these would best describe the resulsts Mathew would see if he was using a conductivity apparatus in each of the different acid concentration. The correct answer is C. This is because, acids conduct electricity, the stronger the acid, the brighter the electricity that will be produced while the weaker the acid, the weaker the electricity that will be produced. Thus, higher concentration equals tronger electricity.</span>
Since they can still be unstable...nuetral atoms have the same amount of protons to electrons but to be stable they need to fill up there outer shell by gaining or losing electrons
The question is incomplete, complete question is :
A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
The final volume of the solution will be 0.236 L.
Explanation:
Concentration of sodium carbonate solution before dilution =
Volume of sodium carbonate solution before dilution = 
Concentration of sodium carbonate solution after dilution =
Volume of sodium carbonate solution after dilution = 
Dilution equation is given by:
1 mL = 0.001 L
236 mL = 0.236 L
The final volume of the solution will be 0.236 L.
the oxidation reaction between oxygen and sodium produces sodium oxide. In many cases, an element may form more than one oxide.
Explanation:
<span>a decrease in Km and an increase in Vmax
km is the constant that relates how thick the volume of the substrate in terms of concentration when the speed is a large portion of the most extreme. They increment Km by meddling with the joining process that makes them stick together wit the substrate, however they have any effect with regards to Vmax since since the sticking process to ES did not occur</span>
